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Zina [86]
2 years ago
6

1. A line goes through the points (4, 5) and (2, -6). Write the equation of the line in point-slope form. Show your work for ful

l credit. (Show how you went from those two points to having the equation in point-slope form?) Circle your answer (4 points)
Mathematics
1 answer:
Hitman42 [59]2 years ago
5 0
1. Find Slope
m = y2-y1/x2-x1
m = -6 - 5/2-4
m = -11/-2
m = 11/2

2. Write equation with know information
y = mx + b
y = 11/2x + b


3. Choose any of the two points (doesn’t matter which in you choose) and replace the x and y value into the equation
y = 11/2x + b (4,5)
5 = 11/2(4) + b
5 = 22 + b

Use algebra and solve for b
5 - 22 = b
b = -17

State all the information you know
m = 11/2 b = -17

Write the equation
y = 11/2x - 17
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\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the Concept of the Functions.

so after plotting the graphs, we get as,

==> m = 2.5

==> b = 0

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a straight line

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Answer:

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Step-by-step explanation:

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What is the axis of symmetry and vertex for the function f(x) = 3(x – 2)2 4?
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we know that

The equation of a vertical parabola in vertex form is equal to

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if a < 0 -----> then the parabola open downward (the vertex is a maximum)

The axis of symmetry is equal to

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In this problem let's analyze two cases

First case

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a=3

so

3 > 0 -----> then the parabola open upward (the vertex is a minimum)

The axis of symmetry is equal to

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Second case

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