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3 years ago

PLX HELP! Need this ASAP! Thx so much!

1 answer:

5 0

2x + 3 + x = 24. Add all like terms
3x + 3 = 24 subtract 3 from each side
3x = 24 divide each side by 3
x = 7

17 students got A’s and 7 students got Lower grades

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-5(x - 4) + 6 = 5(3x+4) -4

jenyasd209 [6]

Answer:

x=1/2

Step-by-step explanation:

-5(x - 4) + 6 = 5(3x+4) -4

WE APPLY DISTRIBUTIVE PROPERTY:

-5*x +5*4 + 6 = 5*3x +5*4 -4

-5x + 26 = 15x +20 -4

26 +4 -20=15x+5x

10=20x

x= 10/20

we have:

x=1/2

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3 years ago

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3 years ago

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sladkih [1.3K]

Answer:

$\large\boxed{B.\ \cos(37^o)=\dfrac{x}{14}}$

Step-by-step explanation:

$sine=\dfrac{opposite}{hypotenuse}\\\\cosine=\dfrac{adjacent}{hypotenuse}\\\\tangent=\dfrac{opposite}{adjacent}\\\\\text{We have}\ adjacent=x\ \text{and}\ hypotenuse=14.\\\text{Therefore it's a cosine.}$

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3 years ago

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Elan Coil [88]

Answer:

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Step-by-step explanation:

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3 years ago

I have the first part but I don't know how to do the second part<br><br> h e l p

Debora [2.8K]

$\bf \begin{array}{cll} \stackrel{ordinal}{position}&\stackrel{term}{value}\\ \cline{1-2} 1&12\\ 2&12+d\\ 3&12+d+d\\ 4&12+d+d+d\\ &12+3d \end{array}\qquad \implies ~\hfill \begin{array}{llll} \stackrel{\textit{4th term}}{12+3d}~~=~~\stackrel{\textit{4th value}}{3}\\\\ 3d=-9\implies d = \cfrac{-9}{3}\\\\ \stackrel{\textit{common difference}}{d = -3} \end{array}$

well, we know the common difference is -3, to go from the 4th term to the 8th term, we need to add "d" 4 times or namely 3+4(-3), likewise to go from the 13th term to the 19th term we have to add "d" 6 times, or namely -24 + 6(-3).

$\bf \stackrel{\textit{8th term}}{3+4(-3)}\implies 3-12\implies -9 \\\\\\ \stackrel{\textit{19th term}}{-24 + 6(-3)}\implies -24-18\implies -42$

3 0

3 years ago