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bulgar [2K]
3 years ago
8

Thickest part of earth?

Geography
2 answers:
Naily [24]3 years ago
8 0

Answer:

oh sh sorry it's B crust

Explanation:

brainliest rn

Alla [95]3 years ago
8 0

Answer:

a option inner core

have a beautiful day ahead

STAY safe stay happy

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In nuclear fission and fusion reactions mass is converted into energy. The average person in US uses around 100,000,000 J of ene
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Answer:

a) The yearly energy consumption for a US population of 300 million is 3\times 10^{16} J/year

b) The energy that would be released if a 60 kg person were converted entirely into energy is 5.4\times 10^{18} Joules.

c) 180 years would this amount of energy support a population of 300 million.

Explanation:

a) Average energy consumed by single person of US = 100,000,000 J/year

Then 300 million US citizen will consume:

300 million = 300 × 1,000,000 = 3\times 10^8

The yearly energy consumption for a US population :

100,000,000 J/year\times 3\times 10^8=3\times 10^{16} J/year

The yearly energy consumption for a US population of 300 million is 3\times 10^{16} J/year

b) E = m\times c^2

E = Energy from converted mass of m

c = speed of light

Given mass of person = m = 60 kg

E=60 kg\times (3\times 10^8 m/s)^2 = 5.4\times 10^{18} J

c) Energy calculated in part (b) = E=5.4\times 10^{18} J

The yearly energy consumption for a US population  of 300 million in an year = 3\times 10^{16} J/year

Let the that would be supported by 5.4\times 10^{18} Joules of energy be x.

x\times 3\times 10^{16} J/year=5.4\times 10^{18} J

x=\frac{5.4\times 10^{18} J}{3\times 10^{16} J/year}=180 years

180 years would this amount of energy support a population of 300 million.

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