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kodGreya [7K]
2 years ago
15

G = x + y/cx solve for x

Mathematics
1 answer:
riadik2000 [5.3K]2 years ago
3 0

An

Step-by-step explanation:

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Which of the following is (are) the solution(s) to 7|x+2|=-49
garik1379 [7]

Answer:

There are no options to choose from, so I'll just give the solution

Step-by-step explanation:

7x+14= -49

7x= -63

x= -9

Hope this helped and pls brainliest

5 0
3 years ago
Precal help if you could could you answer both. Me finishing this helps me graduate.
oee [108]

Exercise 1:

The easiest way to compute powers of complex numbers is to write them in the form

z = \rho e^{i\theta} = \rho(\cos(\theta)+i\sin(\theta))

In this form, you have

z^n = \rho^n e^{in\theta} = \rho^n(\cos(n\theta)+i\sin(n\theta))

The magnitude of the number is given by

z=a+bi \implies \rho = \sqrt{a^2+b^2}

So, we have

z=-1+\sqrt{3}i \implies \rho = \sqrt{1+3}=2

As for the angle, we have

z=a+bi \implies \theta = \text{atan2}\dfrac{b}{a}

So, we have

z=-1+\sqrt{3}i \implies \theta = \text{atan2}\left(\dfrac{-\sqrt{3}}{-1}\right) = -\dfrac{2\pi}{3}

Finally,

z=-1-\sqrt{3}i = 2\left(\cos\left( -\dfrac{2\pi}{3}\right) + i\sin\left( -\dfrac{2\pi}{3}\right)\right) \implies z^6 = 2^6\left(\cos\left( -4\pi\right) + i\sin\left(-4\pi\right)\right) = 64

Exercise 2:

You simply have to compute the trigonometric function:

\cos\left(-\dfrac{\pi}{4}\right) = \dfrac{\sqrt{2}}{2},\quad \sin\left(-\dfrac{\pi}{4}\right) = -\dfrac{\sqrt{2}}{2}

So, we have

z = \sqrt{2}\left(\dfrac{\sqrt{2}}{2} - i\dfrac{\sqrt{2}}{2}\right) = 1-i

7 0
3 years ago
5.
Paraphin [41]

Step-by-step explanation:

the mean value is the sum of all values divided by how many values there are.

so,

(3 + -5 + 70 + -90 + -13) / 5 = -35/5 = -7

-7° F is the mean temperature of the 5 cities.

3 0
2 years ago
Endpoint: (1,7), midpoint: (-10,10)
algol [13]

The answer is (-21, 13) for The second endpoint.  

Let's start by calling the known endpoint L and the unknown K. We'll call the midpoint M. In order to find this, we must first note that to find a midpoint we need to take the average of the endpoints. To do this we add them together and then divide by 2. So, using that, we can write a formula and solve for each part of the k coordinates. We'll start with just x values.

(Kx + Lx)/2 = Mx

(Kx + 1)/2 = -10

Kx + 1 = -20

Kx = -21

And now we do the same thing for y values

(Ky + Ly)/2 = My

(Ky + 7)/2 = 10

Ky + 7 = 20

Ky = 13

This gives us the final point of (-21, 13)

5 0
3 years ago
Simply<br> (2k-9)^2+(k+2)^2=(2k+1)^2+(k-8)^2
vova2212 [387]

The square of a binomial expands as follows:

(a+b)^2=a^2+2ab+b^2

Expanding all the binomials, we have

4k^2-36k+81+k^2+4k+4=4k^2+4k+1+k^2-16k+64

Sum like terms:

5k^2-32k+85=5k^2-12k+65

Simplify terms appearing on both sides:

-32k+85=-12k+65

Move all terms involving k to the left and all numbers to the right:

-20k=-20

Divide both sides by -20:

k=1

6 0
3 years ago
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