Question

Find the vertex of this function. Is it a maximum or a minimum? y=-3(x + 4)2 + 2

Answer 1

Step-by-step explanation:

The equation given is of the form

$y = a(x - h)^2 + k$

where (h, k) are the coordinates of the vertex. So in this case, the vertex is located at (4, 2). Since a is a negative number (a = -3), this means that the vertex is a maximum because the parabola opens downward.