Read the ages of three people and find the average. Display the result.

____ the styles allows the designer to start from a known baseline, confident that no unwanted styles will creep in from any bro

True [87]

The correct answer is, 'Resetting' the style allows the designer to start from a known baseline, confident that no unwanted styles will creep in from any browser's internal style sheet.

8 0

2 years ago

How does a layered pattern make use of abstraction and encapsulation?

maxonik [38]

Answer and Explanation:

The ways in which a layered pattern make use of encapsulation and abstraction are as follows:

This framework lays its focus mainly on the bundling of related functionalities inside an application into different layer that are vertically stacked over one another.
Functionality in between each layer is related by common function or role.
Communication in between the layers is clear and exact and is coupled loosely.
Providing a layered structure to the application indirectly supports its maintainability and flexibility.

Encapsulation:

Since, features like data type, properties, methods or implementation while designing are not exposed at the boundary of the layer thus No assumptions are required for these features.

Abstraction:

The layered framework abstracts the entire system's view and provides adequate details for better understanding of the roles of each layer individually and the relation that exist between these layers.

7 0

2 years ago

Write a loop that reads positive integers from standard input and that terminates when it reads an integer that is not positive.

Paraphin [41]

Answer:

The program to this question as follows:

Program:

#defining variable and assign value

odd=0

even=0

i=1

print('Input 0 after inserting all number: ') #print message

while i>0: #define loop for check inserting and add all number

i=int(input()) #input value by user end

if (i< 0): #check value is not positive

break

if ((i % 2)==0and(i>0)): #check even number condition

even=even+i #add even numbers

if ((i % 2)!=0and(i>0)): #check odd number condition

odd=odd+i #add odd numbers

print ('Sum of Even number:',even,'and','Sum of Odd number:',odd) #print value

Output:

Input 0 after inserting all number:

1

2

3

5

7

0

Sum of Even number: 2 and Sum of Odd number: 16

Explanation:

In the above python program, three variable is defined, that is "even, odd and i", in which "even and odd" variable assign value that is "0", and the variable i is used for inserting elements from user. In the next line a while loop is defined that inserts numbers in variable "i", in this loop, 3 if block is used that can be defined as follows:

In first if block variable "i", checks that value is non-positive number if this condition is true, it will break the loop.
In second if block this block check even number condition and add in even variable.
In third, if block this block check odd number condition and add in odd variable.

End of the loop we use print function that prints the sum of even numbers and odd numbers.

3 0

2 years ago

What's the answer to this

yarga [219]

Answer:

S

Explanation:

The index operator will address individual characters in the string.

5 0

2 years ago

Write a method that prints on the screen a message stating whether 2 circles touch each other, do not touch each other or inters

beks73 [17]

Answer:

The method is as follows:

public static void checkIntersection(double x1, double y1, double r1, double x2, double y2, double r2){

double d = Math.sqrt(Math.pow((x1 - x2),2) + Math.pow((y1 - y2),2));

if(d == r1 + r2){

System.out.print("The circles touch each other"); }

else if(d > r1 + r2){

System.out.print("The circles do not touch each other"); }

else{

System.out.print("The circles intersect"); }

}

Explanation:

This defines the method

public static void checkIntersection(double x1, double y1, double r1, double x2, double y2, double r2){

This calculate the distance

double d = Math.sqrt(Math.pow((x1 - x2),2) + Math.pow((y1 - y2),2));

If the distance equals the sum of both radii, then the circles touch one another

if(d == r1 + r2){

System.out.print("The circles touch each other"); }

If the distance is greater than the sum of both radii, then the circles do not touch one another

else if(d > r1 + r2){

System.out.print("The circles do not touch each other"); }

If the distance is less than the sum of both radii, then the circles intersect

else{

System.out.print("The circles intersect"); }

}

6 0

2 years ago