Ask question

Ask question

All categories

katen-ka-za [31]

3 years ago

5

The scale drawing car length is 3 cm. If the scale is 1 cm:4 ft, what is the actual car length?

2 answers:

kotegsom [21]3 years ago

6 0

1 cm is equal to 4 and the length is 3cm , so ( 3 • 4 = 12 )

musickatia [10]3 years ago

3 0

12 feet is the answer. 4 times 3 is 12.

You might be interested in

A regular hexagon has an apothem measuring 14 cm and an approximate perimeter of 96 cm.

Mariulka [41]

ANSWER

672cm²

EXPLANATION

The area of a regular hexagon is given by the formula,

$Area = \frac{1}{2} ap$

where a=14cm is the apothem and p=96cm is the perimeter of the regular hexagon.

We substitute the values into the formula,

$Area = \frac{1}{2} \times 14 \times 96 {cm}^{2}$

$Area =672 {cm}^{2}$

Therefore the approximate area of the hexagon is 672cm²

8 0

3 years ago

Read 2 more answers

Help please don’t understand.

sergij07 [2.7K]

Okay so first, area is length times width, so 1/4x*x would be first = 1/4(x^2)=64. Then area or x = 16 or -16

perimeter would be width times two plus length times two. I recommend using math papa to calculate these numbers.

4 0

3 years ago

Help please ASAP!!!!!!

Elodia [21]

The correct answer to your problem is 96

4 0

3 years ago

The values of 60, 62, and 84 were common to both samples. The three values are identified as outliers with respect to the age-gr

postnew [5]

Answer:

Only 60 is an identified outlier

Step-by-step explanation:

Given

<u>Age group: 40 to 50</u>

$Min = 60$ $Q_1 = 70$ $Median= 73$

$Q_3 = 76$ $Max = 85$

<u>Conditions for outlier</u>

$Value > Q_3 + 1.5 * IQR$

$Value < Q_1 - 1.5 * IQR$

<em>See attachment for complete question</em>

<u>Required</u>

Which of 60, 62 and 84 is an outlier of age grout 40 to 50 years

First, calculate the IQR of group 40 to 50.

This is calculated as:

$IQR = Q_3 - Q_1$

Where:

$Q_3 = 76$ and $Q_1 = 70$

So:

$IQR = 76 - 70$

$IQR = 6$

<em>Next, is to test the outlier conditions on each value (i.e. 60, 62 and 84)</em>

<u></u>

<u>Testing 60</u>

<u>Condition 1</u>

$Value > Q_3 + 1.5 * IQR$

$60 > 76 + 1.5 * 6$

$60 > 76 + 9$

$60 > 85$ --- False

<u>Condition 2</u>

$Value < Q_1 - 1.5 * IQR$

$60 < 70 - 1.5 * 6$

$60 < 70 - 9$

$60 < 61$ --- True

<em>Because one of the conditions is true, then 60 is an outlier of group 40 - 50 years</em>

<em></em>

<u>Testing 62</u>

<u>Condition 1</u>

$Value > Q_3 + 1.5 * IQR$

$62> 76 + 1.5 * 6$

$62 > 76 + 9$

$62 > 85$ --- False

<u>Condition 2</u>

$Value < Q_1 - 1.5 * IQR$

$62 < 70 - 1.5 * 6$

$62 < 70 - 9$

$62 < 61$ --- False

<em>Because both conditions are false, then 62 is not an outlier of group 40 - 50 years</em>

<em></em>

<u>Testing 84</u>

<u>Condition 1</u>

$Value > Q_3 + 1.5 * IQR$

$84> 76 + 1.5 * 6$

$84 > 76 + 9$

$84 > 85$ --- False

<u>Condition 2</u>

$Value < Q_1 - 1.5 * IQR$

$84 < 70 - 1.5 * 6$

$84 < 70 - 9$

$84 < 61$ --- False

<em>Because both conditions are false, then 84 is not an outlier of group 40 - 50 years</em>

5 0

3 years ago

Sue is drawing two lines on a coordinate plane. She begins the first line at the origin and ends at (4,3). She begins the 2nd li

ludmilkaskok [199]

Answer:

what is it man

Step-by-step explanation:

im sure u solved it by now

6 0

3 years ago