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2 years ago

HELP ASAP DUE AT 10:10

Mathematics

2 answers:

lozanna [386]2 years ago

5 0

Answer:

1) 128j

2)60k -32

adelina 88 [10]2 years ago

5 0

Sorry but I don’t know that

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Work out 5 x 10^6 / 4 x 10^4<br> Give your answer as an ordinary number.

Angelina_Jolie [31]

Answer:

$1.25 \times {10}^{2} = 125$

Step-by-step explanation:

$\frac{5 \times {10}^{6} }{4 \times {10}^{4} } = \frac{5}{4} \times \frac{ {10}^{6} }{ {10}^{4} } = 1.25 \times {10}^{2} = 125$

5 0

2 years ago

It costs miksel $4 to make a bike bag, if he sells each gor $5. He has made a profit of $16 dollars so far

mixas84 [53]

Answer:

Step-by-step explanation:

5-4 = 1 so total profit would be $1 for each bag.

Because he makes 1 dollar per bag this is a fairly simple to see how many he has but we will pretend its not so you have an idea of how to do this later.

You should divide the final profit he's made by the total he gets per each, which would give you how many he has made.

$16/$1 = 16 bags produced.

4 0

2 years ago

Evaluate each expression<br> 6! =<br> 3! • 2=<br> 31

Airida [17]

<h2><u>N-FACTORIAL!</u></h2>

<h3> $\mathbb{ \color{brown} \: PROBLEM } \: \: \bold{{ \color{brown}{1}}} :$ </h3>

$\mathcal{SOLUTION: }$

$\: \bold{ \red{6!}= 6×5×4×3×2×1= \boxed{ \bold{ \blue{720}}}}$

Therefore, <u>the value of 6! is 720</u>.

━┈─────────────────────┈━

<h3> $\mathbb{ \color{brown} \: PROBLEM } \: \: \bold{{ \color{brown}{2}}} :$ </h3>

$\mathcal{SOLUTION: }$

$\bold{3! \cdot 2! }\implies \bold{(3×2×1) \cdot( 2×1 )}$

$\: \: \: \: \: \: \: \: \: \: \: \: \implies \: \bold{ 6 \times 2} = \boxed{ \bold{ \blue{12}}}$

Therefore, <u>the value of the given expression is 12.</u>

━┈─────────────────────┈━

<h3><u>EXPLANATION</u><u>:</u></h3>

The mathematical symbol n! is read as "n factorial". The exclamation point "!" is read as factorial. And please remember or take note that 0! is equal to 1, and 1! is also equal to 1.

_______________∞_______________

6 0

2 years ago

(√2)^3<br><img src="https://tex.z-dn.net/?f=%20%28%5Csqrt%7B2%29%20%7B%3F%7D%5E%7B3%20%5C%5C%7D%20" id="TexFormula1" title=" (\s

Vedmedyk [2.9K]

$\sf \left(\sqrt{2}\right)^3\\\\\\\\\boxed{\sf \mathrm{Apply\:radical\:rule}:\quad \sqrt{a}=a^{\frac{1}{2}}}\\\\\\\\\sf \left(2^{\frac{1}{2}}\right)^3\\\\\\\\\boxed{\sf\mathrm{Apply\:exponent\:rule}:\quad \left(a^b\right)^c=a^{bc} }\\\\\\\\\sf \sf 2^{\frac{1}{2}\cdot \:3}\\\\\\\\\sf 2^{\frac{3}{2}}\\\\\\\\\sf 2^{\frac{3}{2}}=2^{1+\frac{1}{2}}\\\\\\\\\sf 2^{1+\frac{1}{2}}\\\\\\\\\boxed{\sf \mathrm{Apply\:exponent\:rule}:\quad \:x^{a+b}=x^ax^b}\\\\\\\\\sf$