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Brut [27]
3 years ago
13

Which relation is a function?

Mathematics
2 answers:
Alja [10]3 years ago
3 0

Answer:

the answer is the first option.

miskamm [114]3 years ago
3 0

Answer:

  • Option A

Step-by-step explanation:

A)  {(1, 3), (2, 6), (3, 9), (4, 12)} - Yes, all input-outputs are unique  

B) {(1,4), (1, 3), (1, 2), (1, 1) - No, repeat inputs (1)

C) {(3, 4), (2, 4), (5, 1), (3,5)} - No, repeat inputs (3)  

D) {(3, 4), (3, 3), (1, 2), (1,5)} - No, repeat inputs (1 and 3)

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The circumference would be 30 ft, which comes from 6 people have 5ft of space each.  6 x 5 = 30.  Which means the diameter is 9.55414013; Circumference divided by pi is the diameter.  Once you divide the diameter by 2 for the radius, you get 4.777 which can be used to find the area of the table top.  Area is pi x radius x radius = 3.14 x 4.777 x 4.777 =71.654 ft^2
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3 years ago
The price of products may increase due to inflation and decrease due to depreciation. Marco is studying the change in the price
inn [45]

Answer:

Product A has a greater percentage change in price.

Step-by-step explanation:

Part A:

The price f product A, f (<em>x</em>) after <em>x</em> years is given by: 

 f(x) = 0.69\cdot(1.03)^{x}

After <em>x</em> = 0 years, the price of product A is:

f(0) = 0.69\cdot(1.03)^{0}=0.69

After <em>x</em> = 1 years, the price of product A is:

f(1) = 0.69\cdot(1.03)^{1}=0.69\cdot (1+0.03)=0.69\cdot (1+3\%)

After 1 year, the price of product A is 3% times more than the original price.

This means that after one year, the new price is 103% of the original price, which means the price product A is increasing by 3%.

Again after <em>x</em> = 2 years, the price of product A is:

f(2) = 0.69\cdot(1.03)^{2}=[0.69\cdot (1+3\%)]\times (1.03)

This implies that after 2 years, the price of product A is 103% of the price after year 1.

This implies that the price of product A is 3% more than the previous year.

Thus, the price of product A is increasing each year by 3%.

Part B:

The data for Product B is as follows:

Time (t)          Price [f (t)]

   1                   10,100

   2                   10,201

   3                 10,303.01

   4                 10,406.04

Product B is clearly increasing in price.

Consider the changes in price of Product B in the following intervals of years:

  • Year 1 - Year 2:

Price in year 1 = $10,100

Price in Year 2 = $10,201

Compute the increase percentage as follows:

\text{Increase}\%=\frac{10201-10100}{10100}=0.01=1\%

  • Year 2 - Year 3:

Price in Year 2 = $10,201

Price in year 3 = $10,303.01

Compute the increase percentage as follows:

\text{Increase}\%=\frac{10303.01-10201}{10201}=0.01=1\%

  • Year 3 - Year 4

Price in year 3 = $10,303.01

Price in Year 4 = $10,406.04

Compute the increase percentage as follows:

\text{Increase}\%=\frac{10,406.04-10303.01}{10303.01}=0.09999\approx 0.01=1\%

It is quite clear that the price of product B increases by 1% each year.

Thus, Product A has a greater percentage change in price.

3 0
3 years ago
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Anon25 [30]

Answer:

Step-by-step explanation:

Red:black = 1:1

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Now 8 red cards are removed

So, No. of red cards = 24 - 8 =16

Red: Black = 16:24

=\frac{16}{24}=\frac{2}{3}

Red: Black = 2:3

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