The consecutive positive integers would be: x and (x+1),
We would have to solve the following equation to find these numbers:
x(x+1)-[x+(x+1)]=29
x²+x-2x-1=29
x²-x-30=0
x=[1⁺₋√(1+120)]/2
x=(1⁺₋11)/2
We have two possible solutions:
x₁=(1-11)/2=-5 then: (x+1)=-5+1=-4 This is not the solution.
x₂=(1+11)/2=6 then: (x+1)=6+1=7 This solution is right.
Answer: the numbers would be 6 and 7.
Answer:
0.24
Step-by-step explanation:
also i see what you did there
Let
be an integer. Suppose there is a triangle with legs of length 16 and
. Then by the Pythagorean theorem, the length of the hypotenuse should be
The formulas for Pythagorean triples say that if the legs are integers, then so must be the hypotenuse, because if
and
are integers, then so are
,
, and
.
However,
is not a perfect square trinomial, which means for any integer
, the length of the hypotenuse is not an integer, so such a triangle doesn't exist.
Answer:
$75
Step-by-step explanation:
50+75=125
125 x 0.6= 75
Steve gives 75 dollars to his mother