Please solve the math problem for me... I will mark you brainliest

How do you write this equation<br>(y-18)<br>y<br>x<br>it's inside a triangle

ohaa [14]

<h2>Answer:</h2>

(y-18)(y+x)

<h2>Explanation step-by-step:</h2>

<h3>Given data:</h3>

u have been provided with:

(y-18)
y
x

<h3>Formula:</h3>

so for solving it u have to make a equation first so choose wisely now make the equation but how?

<h3>Solution:</h3>

first of all take

(y-18)(y+x)

this will be ur equation as both the variables x and y given to u r positive(+) so this can be one equation.

6 0

3 years ago

Two numbers are in the ratio 7:10 If the larger number is 140,what is the smaller number

nydimaria [60]

Given that nos. are in ratio 7:10

The larger no. is 140

Let the smaller no. be x

Using ratio and proportion

7 : 10 :: x : 140

⇒10 × x = 140 × 7

$⇒x = \frac{140 \times 7}{10} = 98 \\$

<em>-</em><em> </em><em>BRAINLIEST</em><em> ANSWERER</em>

3 0

3 years ago

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The n candidates for a job have been ranked 1, 2, 3,..., n. Let X 5 the rank of a randomly selected candidate, so that X has pmf

jeka57 [31]

Question:

The n candidates for a job have been ranked 1, 2, 3,..., n. Let x = rank of a randomly selected candidate, so that x has pmf:

$p(x) = \left \{ {{\frac{1}{n}\ \ x=1,2,3...,n} \atop {0\ \ \ Otherwise}} \right.$

(this is called the discrete uniform distribution).

Compute E(X) and V(X) using the shortcut formula.

[Hint: The sum of the first n positive integers is $\frac{n(n +1)}{2}$ , whereas the sum of their squares is $\frac{n(n +1)(2n+1)}{6}$

Answer:

$E(x) = \frac{n+1}{2}$

$Var(x) = \frac{n^2 -1}{12}$ or $Var(x) = \frac{(n+1)(n-1)}{12}$

Step-by-step explanation:

Given

PMF

$p(x) = \left \{ {{\frac{1}{n}\ \ x=1,2,3...,n} \atop {0\ \ \ Otherwise}} \right.$

Required

Determine the E(x) and Var(x)

E(x) is calculated as:

$E(x) = \sum \limits^{n}_{i} \ x * p(x)$

This gives:

$E(x) = \sum \limits^{n}_{x=1} \ x * \frac{1}{n}$

$E(x) = \sum \limits^{n}_{x=1} \frac{x}{n}$

$E(x) = \frac{1}{n}\sum \limits^{n}_{x=1} x$

From the hint given:

$\sum \limits^{n}_{x=1} x =\frac{n(n +1)}{2}$

So:

$E(x) = \frac{1}{n} * \frac{n(n+1)}{2}$

$E(x) = \frac{n+1}{2}$

Var(x) is calculated as:

$Var(x) = E(x^2) - (E(x))^2$

Calculating: $E(x^2)$

$E(x^2) = \sum \limits^{n}_{x=1} \ x^2 * \frac{1}{n}$

$E(x^2) = \frac{1}{n}\sum \limits^{n}_{x=1} \ x^2$

Using the hint given:

$\sum \limits^{n}_{x=1} \ x^2 = \frac{n(n +1)(2n+1)}{6}$

So:

$E(x^2) = \frac{1}{n} * \frac{n(n +1)(2n+1)}{6}$

$E(x^2) = \frac{(n +1)(2n+1)}{6}$

So:

$Var(x) = E(x^2) - (E(x))^2$

$Var(x) = \frac{(n+1)(2n+1)}{6} - (\frac{n+1}{2})^2$

$Var(x) = \frac{(n+1)(2n+1)}{6} - \frac{n^2+2n+1}{4}$

$Var(x) = \frac{2n^2 +n+2n+1}{6} - \frac{n^2+2n+1}{4}$

$Var(x) = \frac{2n^2 +3n+1}{6} - \frac{n^2+2n+1}{4}$

Take LCM

$Var(x) = \frac{4n^2 +6n+2 - 3n^2 - 6n - 3}{12}$

$Var(x) = \frac{4n^2 - 3n^2+6n- 6n +2 - 3}{12}$

$Var(x) = \frac{n^2 -1}{12}$

Apply difference of two squares

$Var(x) = \frac{(n+1)(n-1)}{12}$

3 0

3 years ago

What is the slope of the line that goes through the points (1, -5) and (4, 1)

tangare [24]

Answer:

D) 2

Step-by-step explanation:

Use the following slope formula:

<em>m </em>(slope) = (y₂ - y₁)/(x₂ - x₁)

Let:

(x₁ , y₁) = (4 , 1)

(x₂ , y₂) = (1 , -5)

Plug in the corresponding numbers to the corresponding variables:

<em>m</em> = (-5 - 1)/(1 - 4)

Simplify. Remember to follow PEMDAS. First subtract, then divide:

<em>m</em> = (-5 - 1)/(1 - 4)

<em>m</em> = (-6)/(-3)

<em>m</em> = 2

D) 2 is your answer.

~

7 0

4 years ago

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Take a look at the picture and answer correctly so i can mark you as brainliest.

AVprozaik [17]

Answer:

{-5, -4, -2, -1, 2, 3}

Step-by-step explanation:

Domain is x value and then you have to put in order :)

5 0

3 years ago

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