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Keith_Richards [23]
3 years ago
9

Heather makes 9 dollars for each hour of work. Write and equation to represent her total pay (p) after working (h) hours.

Mathematics
1 answer:
Valentin [98]3 years ago
3 0

Answer:

9h=p

Step-by-step explanation:

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liraira [26]
\bf \sqrt{2}\left(3\sqrt{2}+\sqrt{18}  \right)~~
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18=2\cdot 3\cdot 3\\
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\end{cases}\implies \sqrt{2}\left(3\sqrt{2}+\sqrt{2\cdot 3^2}  \right)
\\\\\\
\sqrt{2}\left(3\sqrt{2}+3\sqrt{2}  \right)\implies \sqrt{2}\left(6\sqrt{2} \right)\implies 6\left(\sqrt{2}\right)^2\implies 6\cdot 2\implies \stackrel{rational}{12}
7 0
3 years ago
Due NOW!!! Please help!
tia_tia [17]

Answer:

At x = 7 and x= 1

Step-by-step explanation:

Set each equation equal to 0 and solve.

x - 7 = 0

x = 7

x-1 =0

x = 1

4 0
2 years ago
Read 2 more answers
What is the y-intercept of y = –3x + 6?
tankabanditka [31]
The Answer Is -3(x-2)
5 0
3 years ago
Read 2 more answers
2.the solution set of x +y =5 and x-y =3
Nataliya [291]

Answer:

Check the solution below

Step-by-step explanation:

2) Given the equation

x +y =5... 1 and

x-y =3 ... 2

Add both equations

x+x = 5+3

2x = 8

x = 8/2

x = 4

Substitute x = 4 into 1:

From 1: x+y = 5

4+y= 5

y = 5-4

y = 1

3) Given

x+3y =15 ... 1

2x+7y=19 .... 2

From 2: x = 15-3y

Substitute into 2

2(15-3y)+7y = 19

30-6y+7y = 19

30+y = 19

y = 19-30

y = -11

Substitute y=-11 into x = 15-3y

x =15-3(-11)

x = 15+33

x = 48

The solution set is (48, -11)

4) given

x/2 +y/3 =0 and x+2y=1

From 1

(3x+2y)/6 = 0

3x+2y = 0.. 3

x+2y= 1... 4

From 4: x = 1-2y

Substutute

3(1-2y) +2y = 0

3-6y+2y = 0

3 -4y = 0

4y = 3

y = 3/4

Since x = 1-2y

x = 1-2(3/4)

x = 1-3/2

x= -1/2

The solution set is (-1/2, 3/4)

5) Given

5.x=1/2 and y =x +1 then solution is

We already know the vkue of x

Get y

y= x+1

y = 1/2 + 1

y = 3/2

Hence the solution set is (1/2, 3/2)

6) Given

3x +y =5 and x -3y =5

From 3; x = 5+3y

Substitute into 1;

3(5+3y)+y = 5

15+9y+y = 5

10y = 5-15

10y =-10

y = -1

Get x;

x = 5+3y

x = 5+3(-1)

x = 5-3

x = 2

Hence two solution set is (2,-1)

6 0
2 years ago
Is a measure of 26 inches​ "far away" from a mean of 16 ​inches? As someone with knowledge of​ statistics, you answer​ "it depen
alexandr402 [8]

Answer: Hello!

In a normal distribution, between the mean and the mean plus the standar deviation, there is a 34.1% of the data set, between the mean plus the standar deviation, and the mean between two times the standard deviation, there is a 16.2% of the data set, and so on.

If our mean is 16 inches, and the measure is 26 inches, then the difference is 10 inches between them.

a) if the standar deviation is 2 inches, then you are 10/2 = 5 standar deviations from the mean.

b) yes, is really far away from the mean, in a normal distribution a displacement of 5 standar deviations has a very small probability.

c) Now the standar deviation is 7, so now 26 is in the range between 1 standar deviation and 2 standar deviations away from the mean.

Then this you have a 16% of the data, then in this case, 26 inches is not far away from the mean.

3 0
2 years ago
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