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liq [111]
3 years ago
13

What is the slope y, equals, x, plus, 5?

Mathematics
2 answers:
musickatia [10]3 years ago
6 0
1/5 is the slope. Hope this helps
Blizzard [7]3 years ago
4 0

Answer:

slope = m = 1

Step-by-step explanation:

y = x + 5

slope intercept form is y = mx + b, where m is the slope.

in this case, the m = 1; therefore, the slope is 1

You might be interested in
A roof has a cross section that is a right triangle. The diagram shows the approximate dimensions of this cross section. Find th
nordsb [41]

Answer:

5

Step-by-step explanation:

Area of right angle Triangle:

6.5 * 9 * 1/2 = 29.25

2nd way to find area:

1/2 * base * height

Since we have area and base:

1/2 * 11.1 * h = 29.25

= 5.27m

= 5m (nearest tenth)

8 0
3 years ago
Solve.<br> 3^x+1 = 9^ 5x<br> a. x=3<br> b. x = 1/3<br> c. x=9<br> d. x= 1/9
jasenka [17]

Answer:

x = 1/9

Step-by-step explanation:

3^ (x+1) = 9 ^ (5x)

Replace 9 with 3^2

3^ (x+1) = 3^2 ^ (5x)

We know that a^b^c = a ^(b*c)

3^ (x+1) = 3^(2 * (5x))

3^ (x+1) = 3^(10x)

The bases are the same so the exponents are the same

x+1 = 10x

Subtract x from each side

x+1-x = 10x-x

1 = 9x

Divide each side by 9

1/9 = 9x/9

1/9 =x

8 0
3 years ago
BRAINLIEST IF CORRECT ASAP
TEA [102]

Based on the definition of an angle bisector, there is an erro in line 1, because, BC is an angle bisector.

<h3>What is an Angle Bisector?</h3>

An angle bisector is a line segment that bisects an angle into congruent parts.

In the proof given, since C is the incenter of the isoscles triangle ABD, therefore, line segment BC bisects ∠ABD.

This implies that BC is an angle bisector of ∠ABD not altitude.

Therefore, based on the definition of an angle bisector, there is an erro in line 1, because, BC is an angle bisector.

Learn more about an angle bisector on:

brainly.com/question/24334771

5 0
2 years ago
The upper arm length of females over 20 years old in a country is approximately Normal with mean 35.8 centimeters (cm) and stand
lana [24]

Answer:

a) The range of lengths from 28.3 cm to 43.3 cm covers almost all (99.7%) of this distribution.

b) 16% of women over 20 have upper arm lengths less than 33.3 cm.

Step-by-step explanation:

The Empirical Rule(68-95-99.7 Rule) states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 35.8 cm

Standard deviation = 2.5 cm

(a) What range of lengths covers almost all (99.7%) of this distribution?

This range is from 3 standard deviations below the mean to three standard deviations above the mean.

So from 35.8 - 3*2.5 = 28.3 cm to 35.8 + 3*2.5 = 43.3 cm

The range of lengths from 28.3 cm to 43.3 cm covers almost all (99.7%) of this distribution.

(b) What percent of women over 20 have upper arm lengths less than 33.3 cm?

68% of the women over 20 have upper arm length between 33.3 cm and 38.3 cm. The other 32% have upper arm length lower than 33.3 cm or higher than 38.3. The distribution is symmetric, so 16% of the have upper arm length lower than 33.3 cm and 16% have upper arm length higher than 38.3 cm

So 16% of women over 20 have upper arm lengths less than 33.3 cm.

4 0
3 years ago
Simplify. Show your work. 5-1/3 + (-3-9/18)
Ipatiy [6.2K]

You have to use PEMDAS, it stands for parenthesis, exponents, multiplication, division, addition, and subtraction. So first you have to subtract the numbers in the parenthesis which is -3.5 (9/18=1/2). Since there are no exponents or multiplying or dividing, we skip those. Now, we do 5-1/3 and we get 4 2/3. Lastly, add 4 2/3 and -3.5(which is equal to -3 1/2). We get 2 1/6=13/6=1.166666667

I hope this helps!

4 0
3 years ago
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