Question

Consider the chemical equation. CuCl2 2NaNO3 Right arrow. Cu(NO3)2 2NaCl What is the percent yield of NaCl if 31.0 g of CuCl2 reacts with excess NaNO3 to produce 21.2 g of NaCl? Use Percent yield equals StartFraction actual yield over theoretical yield EndFraction times 100.. 49.7% 58.4% 63.6% 78.7%

Answer 1

Answer:

78.7% or D

Explanation:

Edg 2021