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nikklg [1K]
3 years ago
15

Which pairs of quadrilaterals can be shown to be congruent using rigid motions?

Mathematics
1 answer:
Tju [1.3M]3 years ago
5 0

Answer:

yes ur right

Step-by-step explanation:

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QUESTION<br> WORTH<br> 20 POINTS!!! HELP ASAP PLEASE<br> why am i alive
guajiro [1.7K]

Answer:

Cause you were born, as simple as that. Plenty of people deal with harsh life.

Step-by-step explanation:

That's not a math question BUT

4 0
2 years ago
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In a certain constituency, there are 8 500 voters and
babymother [125]

First let's find how much is 15% of 8500 voters.

To do that, we can multiply 15 by 8500 and then divide by 100.

Work: 15 x 8500 = 127500

127500/100 = 1275

Therefore 15 percent of 8500 is 1275.

Then, we subtract 1275 from 8500 to find the amount of people who did vote.

8500 - 1275 = 7,225

Thus, 7,225 people voted while 1,275 people did not.

8 0
3 years ago
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38 centimeters=_or_meters
KATRIN_1 [288]
38 centimeters = 0.38 meters 
6 0
3 years ago
Use a paragraph, flow chart, or two-column proof to prove the angle congruency. Given: ∠ CXY ≅ ∠ BXY
Llana [10]

Answer:

See explanation

Step-by-step explanation:

Consider triangles CAX and BAX. In these triangles,

  • \overline{AC}\cong \overline{AB} - given
  • \angle CAX\cong \angle BAX - given
  • \overline{AX}\cong \overline{AX} - reflexive property

By SAS postulate, \triangle CAX\cong \triangle BAX

Congruent triangles have conruent corresponding parts. So,

\overline{CX}\cong \overline{BX}

Consider triangles CXY and BXY. In these triangles,

  • \overline{CX}\cong \overline{BX} - proven
  • \angle CXY\cong \angle BXY - given
  • \overline{XY}\cong \overline{XY} - reflexive property

By SAS postulate, \triangle CXY\cong \triangle BXY

Congruent triangles have conruent corresponding parts. So,

\angle XCY\cong \angle XBY

5 0
3 years ago
Find the values of m and b that make the following function differentiable.
Sonbull [250]
The derivative of f(x) at x=3 is 2x=6 approaching from the left side (apply power rule to y=x^2). The derivative of f(x) at x=3 is m approaching from the right side. In order for the function to be differentiable, the limit of derivative at x=3 must be the same approaching from both sides, so m=6. Then, x^2=mx+b at x=3, plug in m=6, 9=18+b, so b=-9.
7 0
3 years ago
Read 2 more answers
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