Answer:
Answer is 
Step-by-step explanation:
To find the interval of x. Use our equations to equal each other.
Integrate.
![\frac{-x^3}{3}+x^2\\(\frac{-2^3}{3}+2^2)-[\frac{-0^3}{3}+0^2]\\-\frac{8}{3} +4-0\\-\frac{8}{3}+\frac{12}{3} =4/3](https://tex.z-dn.net/?f=%5Cfrac%7B-x%5E3%7D%7B3%7D%2Bx%5E2%5C%5C%28%5Cfrac%7B-2%5E3%7D%7B3%7D%2B2%5E2%29-%5B%5Cfrac%7B-0%5E3%7D%7B3%7D%2B0%5E2%5D%5C%5C-%5Cfrac%7B8%7D%7B3%7D%20%2B4-0%5C%5C-%5Cfrac%7B8%7D%7B3%7D%2B%5Cfrac%7B12%7D%7B3%7D%20%20%3D4%2F3)
Using Desmos I have Graphs of both of the equations you have provided. The problem asks us to find the shaded region between those curves/equations.
Proof Check your interval of x.
The sum is 45577788999000866;33sorry
Answer:
1, 1/2, 3/2
Step-by-step explanation:
This is a prism (a 3d rectangle) and so your formula for finding the volume is V= L x W x H.
For the prism:
L= 1 (4 cubes x 1/4 = 4)
W = 1/2 (2 cubes x 1/4 = 1/2)
H = 3/2 (6 cubes x 1/4 = 6/4 = 3/2)
That's your answer, the tile 1, 1/2, 3/2
Well first divide 12×85=___ ÷340
Answer:
y = 3x-15 and y = x-7
Step-by-step explanation:
We are asked to write a system of equations with the solution (4,-3)
It is sufficient if we find two lines passing through this point.
Let us take first line as with slope 3.
Then the equation would be of the form
y-y1 = m(x-x1)
y+3 = 3(x-4)
Or y = 3x-15 is one line
Let second line have slope 1
y+3 = 1(x-4)
y = x-7
Now we have two systems of equations as
y = 3x-15 and y = x-7
