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sp2606 [1]
3 years ago
15

If it is assumed that the heights of men are normally distributed with a standard deviation of 2.5 inches, how large a sample sh

ould be taken to be fairly sure (probability 0.95) that the sample mean does not differ from the true mean (population mean) by more than 0.90 in absolute value? (Round your answer up to the nearest whole number.)
Mathematics
1 answer:
Volgvan3 years ago
7 0

Answer:

30 men

Step-by-step explanation:

In order to be sure that the sample mean does differ from the population mean by more than 0.90, the sample size (n) that should be used is given by:

0.90 < Z\frac{s}{\sqrt{n}}

Where 'Z' , for a 95% probability is 1.960, 's' is the standard deviation of 2.5 inches:

0.90 > 1.960\frac{2.5}{\sqrt{n}}\\n >(\frac{1.960*2.5}{0.9})^2\\n>29.64

Rounding up to the nearest whole number, the sample size should be at least 30 men.

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Help me solve problem one please.
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Answer: His temperature is 99°F

Step-by-step explanation:

Let's state what we know:

Steve's temperature was initially 102°F

Later it dropped 3°F lower

Since his temperature decreased we need to subtract 3 from 102 to see what his temperature is now

102-3=99

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Answer:

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Step-by-step explanation:

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Deidre does not think exercise makes a difference in weight loss when trying to lose weight. She gets two random samples of the
melamori03 [73]

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3 years ago
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3/4

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36/48

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Answer:

x = 17 and y = 8

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Therefore, you can set them equal to each other and solve for x.

8x - 31 = 6x + 3

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