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2 years ago

What is the value of the expression?

Mathematics

1 answer:

FromTheMoon [43]2 years ago

8 0

Step-by-step explanation:

15X - 4Y when X=7 Y=8

=15*(7) - 4*(8)

= 105 - 32

=73

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3 years ago

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Last year, Scout Troop # 85 sold 540 boxes of cookies. This year, they sold 783 boxes. What was the percent increase in the numb

lesantik [10]

Difference/original
783 - 540 = 243
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3 years ago

20 POINTS

RUDIKE [14]

<em>The correct expressions are as follows:</em>

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}}$ Equivalent $343$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}}$ Not Equivalent $49$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}}$ Equivalent $7^{\frac{1}{5}} \cdot 7^{\frac{14}{5}}$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}}$ Not Equivalent $49^{\frac{2}{10}} \cdot 7^{\frac{1}{5}}$

$\texttt{ }$

<h3>Further explanation</h3>

Let's recall following formula about Exponents and Surds:

$\boxed { \sqrt { x } = x ^ { \frac{1}{2} } }$

$\boxed { (a ^ b) ^ c = a ^ { b . c } }$

$\boxed {a ^ b \div a ^ c = a ^ { b - c } }$

$\boxed {\log a + \log b = \log (a \times b) }$

$\boxed {\log a - \log b = \log (a \div b) }$

<em>Let us tackle the problem!</em>

$\texttt{ }$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = 7^{\frac{1}{5}} \cdot (7^2)^{\frac{7}{5}}$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = 7^{\frac{1}{5}} \cdot (7)^{2\times \frac{7}{5}}$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = \boxed{7^{\frac{1}{5}} \cdot 7^{\frac{14}{5}}}$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = 7^{\frac{1}{5} + \frac{14}{5}}$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = 7^{\frac{15}{5}}$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = 7^{3}$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = \boxed{343}$

$\texttt{ }$

<em>From the results above, it can be concluded that the correct statements are:</em>

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}}$ Equivalent $343$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}}$ Not Equivalent $49$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}}$ Equivalent $7^{\frac{1}{5}} \cdot 7^{\frac{14}{5}}$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}}$ Not Equivalent $49^{\frac{2}{10}} \cdot 7^{\frac{1}{5}}$

$\texttt{ }$

<h3>Learn more</h3>

Coefficient of A Square Root : brainly.com/question/11337634
The Order of Operations : brainly.com/question/10821615
Write 100,000 Using Exponents : brainly.com/question/2032116

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Exponents and Surds

Keywords: Power , Multiplication , Division , Exponent , Surd , Negative , Postive , Value , Equivalent , Perfect , Square , Factor.

4 0

4 years ago

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construct a 90% confidence interval of the population proportion using the giver information x=74 n=150

FrozenT [24]

Answer:

The 90% confidence interval of the population proportion is (0.43, 0.56).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population proportion <em>p</em> is:

$CI=\hat p\pm z_{\alpha/2}\ \sqrt{\frac{\hat p(1-\hat p)}{n}}$

The information provided is:

<em>X</em> = 74

<em>n</em> = 150

Confidence level = 90%

Compute the value of sample proportion as follows:

$\hat p=\frac{X}{n}=\frac{74}{150}=0.493$

Compute the critical value of <em>z</em> for 90% confidence level as follows:

$z_{\alpha/2}=z_{0.10/2}=z_{0.05}=1.645$

*Use a <em>z</em>-table.

Compute the 90% confidence interval of the population proportion as follows:

$CI=\hat p\pm z_{\alpha/2}\ \sqrt{\frac{\hat p(1-\hat p)}{n}}$

$=0.493\pm 1.645\times \sqrt{\frac{0.493(1-0.493)}{150}}\\\\=0.493\pm 0.0672\\\\=(0.4258,\ 0.5602)\\\\\approx (0.43,\ 0.56)$

Thus, the 90% confidence interval of the population proportion is (0.43, 0.56).

3 0

3 years ago

What is the scientific notation for 0.00000154

aleksandrvk [35]

1.54x10^-5, hope this helps

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3 years ago

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