Answer: I got 23/10, or 2.3
Step-by-step explanation:
<span>0.08333333333
</span><span>as it is a non recurring decimal fraction
</span>x = 0.083333333
<span>1000x = 83.3333333..... </span>
<span>1000x - x =( 83.333333....) - (0.083333..... )</span>
<span>999x = 83.25 </span>
<span>3996x = 333
</span>x=333/3996
<span>x = 1/12 </span>
Answer:
four less than the quotient of a number cubed and seven, increased by three ![(\frac{n^3}{7} -4)+3](https://tex.z-dn.net/?f=%28%5Cfrac%7Bn%5E3%7D%7B7%7D%20-4%29%2B3)
five times the difference of a number squared and six
![5(n^2 -6)](https://tex.z-dn.net/?f=5%28n%5E2%20-6%29)
nine more than the quotient of six and a number cubed, decreased by four
![9+\frac{6}{n^3}-4](https://tex.z-dn.net/?f=9%2B%5Cfrac%7B6%7D%7Bn%5E3%7D-4)
twice the difference of nine and a number squared
![2(9-n^2)](https://tex.z-dn.net/?f=2%289-n%5E2%29)
Step-by-step explanation:
Let n the number of interest we have this:
four less than the quotient of a number cubed and seven, increased by three ![(\frac{n^3}{7} -4)+3](https://tex.z-dn.net/?f=%28%5Cfrac%7Bn%5E3%7D%7B7%7D%20-4%29%2B3)
five times the difference of a number squared and six
![5(n^2 -6)](https://tex.z-dn.net/?f=5%28n%5E2%20-6%29)
nine more than the quotient of six and a number cubed, decreased by four
![9+\frac{6}{n^3}-4](https://tex.z-dn.net/?f=9%2B%5Cfrac%7B6%7D%7Bn%5E3%7D-4)
twice the difference of nine and a number squared:
![2(9-n^2)](https://tex.z-dn.net/?f=2%289-n%5E2%29)
Answer:
x = 55.065
Step-by-step explanation:
Side a = 87.49965
Side b = 55.06531
Side c = 68
Angle ∠A = 90° = 1.5708 rad = π/2
Angle ∠B = 39° = 0.68068 rad
Angle ∠C = 51° = 0.89012 rad
Area = 1,872.22068
Perimeter p = 210.56496
Semiperimeter s = 105.28248
The answer to 8a. is 17, the answer to 8b. is 3.9, the answer to 8c. is 1 / 2, the answer to 8d. is 7 7 / 8, the answer to 9a. is commutative property, the answer to 9b. is multiplicative identity property, the answer to 9c. is associative property, and the answer to 9d. is additive inverse property.
Regarding the whole "explain using mental math" thing, I pretty much just used the fact that 8a. and 8b. both had the same number of decimal places. For 8c., I just made each number have a denominator of 10. And last, for 8d., all of the denominators were already the same, which made it pretty easy. I apologize for this section of my answer being so informal lol, I haven't had to do these kinds of problems in like 5 years <span />