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nikklg [1K]
4 years ago
15

Irene is going to read a 216-page book. If she reads at a rate of 18 pages per day, how many days will it take her to read 1/3 o

f the book?
Mathematics
2 answers:
Ainat [17]4 years ago
7 0
216pg ÷ 3 = 72

72pg ÷ 18pg per day = 4 days

The answer is 4 days.
Molodets [167]4 years ago
3 0
It will take her 4 days to read 1/3 of the book.

The answer is 4.
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What is 3/8 as a decimal
Alex Ar [27]
The answer would be 0.375
7 0
2 years ago
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A ship at position (1, 0) on a nautical chart (with north in the positive y direction) sights a rock at position (7, 5). What an
Romashka-Z-Leto [24]

Answer:

0.69473828 radians east of north.

Step-by-step explanation:

Interpreting the information given on a Cartesian plane, the position of the ship will be (1,0) and that of the rock will be (7,5). Connecting the point (1,0) and (7,5) with a line and dropping a perpendicular line from point (7,5) to the x-axis to intersect the x-axis at (7,0), will form a right-triangle with base length 6 units and a height of 5 units.

<u>Finding the base length from points (1,0) and (7,0)</u>

d=√(x₂-x₁)²+(y₂-y₁)²

d=√(7-1)²

d= √6²

d=6 units

<u>Finding the height from points (7,5) and (7,0)</u>

d=√(x₂-x₁)²+(y₂-y₁)²

d=√(7-7)² + (0-5)²

d=√-5²

d=√25

d=5 units

So you now have a right triangle with base length 6 units and height 5 units.

To get the bearing of rock from ship position you apply the formula for tangent of an angle

Tan Ф = length of opposite side/length of adjustment side

TanФ=5/6

Tan Ф =0.83333333333

Tan⁻¹ (0.83333333333) =0.69473828 radians east of north.

3 0
3 years ago
87 less than the quotient of an unknown number and 43 is -75
Dafna11 [192]
Hm...maybe searching it up on google can help you...
3 0
3 years ago
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Maci and I are making a small kite. Two sides are 10". Two sides are 5". The shorter diagonal is 6". Round all your answers to t
Art [367]

Answer:

A. 4".

B. Approximately 9.54".

C. Approximately 13.54".

Step-by-step explanation:

Please find the attachment.

Let x be the distance from the peak of the kite to the intersection of the diagonals and y be the distance from the peak of the kite to the intersection of the diagonals.

We have been given that two sides of a kite are 10 inches and two sides are 5 inches. The shorter diagonal is 6 inches.

A. Since we know that the diagonals of a kite are perpendicular and one diagonal (the main diagonal) is the perpendicular bisector of the shorter diagonal.

We can see from our attachment that point O is the intersection of both diagonals. In triangle AOD the side length AD will be hypotenuse and side length DO will be one leg.

We can find the value of x using Pythagorean theorem as:

(AO)^2=(AD)^2-(DO)^2

x^{2}=5^2-3^2

x^{2}=25-9

x^{2}=16

Upon taking square root of both sides of our equation we will get,

x=\sqrt{16}

x=\pm 4

Since distance can not be negative, therefore, the distance from the peak of the kite to the intersection of the diagonals is 4 inches.

B. We can see from our attachment that point O is the intersection of both diagonals. In triangle DOC the side length DC will be hypotenuse and side length DO will be one leg.

We can find the value of y using Pythagorean theorem as:

(OC)^2=(DC)^2-(DO)^2

Upon substituting our given values we will get,

y^2=10^2-3^2

y^2=100-9

y^2=91

Upon taking square root of both sides of our equation we will get,

y=\sqrt{91}

y\pm 9.539392

y\pm\approx 9.54

Since distance can not be negative, therefore, the distance from intersection of the diagonals to the top of the tail is approximately 9.54 inches.

C. We can see from our diagram that the length of longer diagram will be the sum of x and y.

\text{The length of the longer diagonal}=x+y

\text{The length of the longer diagonal}=4+9.54

\text{The length of the longer diagonal}=13.54

Therefore, the length of longer diagonal is approximately 13.54 inches.

3 0
3 years ago
#1. Which of the following suffixes means “bearing or producing”? A. -osis B. -oferous C. -fic D. -oid....#2. Which of the follo
AlexFokin [52]
#1-fic
#2 -oid

I took latin suffixes
5 0
3 years ago
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