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ryzh [129]
3 years ago
13

ASAP, HELP ME PLZ I REALLY NEED HELP! YOU'LL GTE BRAINLIEST!

Mathematics
2 answers:
ycow [4]3 years ago
8 0

Answer:

I believe it's D I could be wrong though :(

Hope you have a great day...

goldenfox [79]3 years ago
3 0

Answer:

d

Step-by-step explanation:

add the find the coordinates of the trapezoid then subtract 6 from the x coordinates and add 4 to the y coordinates

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Why did j ernest wilkins jr was the first to do something significant in math
Nuetrik [128]

Answer:

guess hes just smart

Step-by-step explanation:

6 0
3 years ago
HELP PLEASE !!
Kazeer [188]
Bert, Camille, Etsuko
8 0
3 years ago
Dylan Rieder is a statistics student investigating whether athletes have better balance than non-athletes for a thesis project.
Kobotan [32]

Answer:

t=\frac{(3.7-4.1)-0}{\sqrt{\frac{1.1^2}{32}+\frac{1.3^2}{45}}}}=-1.457

p_v =P(t_{75}  

Comparing the p value with a significance level for example \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can't say that the population mean for the athletes is significantly lower than the population mean for non athletes.  

Step-by-step explanation:

Data given and notation

\bar X_{A}=3.7 represent the mean for athletes  

\bar X_{NA}=4.1 represent the mean for non athletes  

s_{A}=1.1 represent the sample standard deviation for athletes  

s_{NA}=1.3 represent the sample standard deviation for non athletes

n_{A}=32 sample size for the group 2  

n_{NA}=45 sample size for the group 2  

\alpha=0.01 Significance level provided  

t would represent the statistic (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the population mean for athletes is lower than the population mean for non athletes, the system of  hypothesis would be:  

Null hypothesis:\mu_{A}-\mu_{NA}\geq 0  

Alternative hypothesis:\mu_{A} - \mu_{NA}< 0  

We don't have the population standard deviation's, we can apply a t test to compare means, and the statistic is given by:  

t=\frac{(\bar X_{A}-\bar X_{NA})-\Delta}{\sqrt{\frac{s^2_{A}}{n_{A}}+\frac{s^2_{NA}}{n_{NA}}}} (1)  

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.  

With the info given we can replace in formula (1) like this:  

t=\frac{(3.7-4.1)-0}{\sqrt{\frac{1.1^2}{32}+\frac{1.3^2}{45}}}}=-1.457

P value  

We need to find first the degrees of freedom given by:

df=n_A +n_{NA}-2=32+45-2=75

Since is a one left tailed test the p value would be:  

p_v =P(t_{75}  

Comparing the p value with a significance level for example \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can't say that the population mean for the athletes is significantly lower than the population mean for non athletes.  

5 0
3 years ago
I need help pls !!!!
Phantasy [73]

Answer:

See Below

Step-by-step explanation:

Ok, so in this problem you have some vertical angles. These are angles oppisites from each other. Therefore; d = 52, f = ?, and e = 77. All the angles added together will = 360. Let's add up the angles we know and subtract the whole from 360.

52 + 52 + 77 + 77 = ?

104 + 154 = 258

360 - 258 = 102

Since we know that f and the unlabeled angle are the same, we need to divide this total between the two of them.

102/2 = 51

Therefore;

d = 52

e = 77

f = 51

3 0
3 years ago
Which of the following best describes the graphs below?
Sati [7]

Answer:

D

Step-by-step explanation:

Look at all possibilities then use  all of them then find out which one matches the best.

8 0
4 years ago
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