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Ray Of Light [21]
3 years ago
9

What is the equation

Mathematics
1 answer:
MAVERICK [17]3 years ago
4 0

9514 1404 393

Answer:

  y = -3x -1

Step-by-step explanation:

We can write the equation in slope-intercept form if we know the slope and the y-intercept.

The slope is ...

  m = "rise"/"run" = (change in y)/(change in x)

We can see that the line passes through grid intersections at (x, y) = (0, -1) and at (1, -4). Between these two points, the change in y is (-4 -(-1)) = -3, and the change in x is (1 -0) = 1. Then the slope is ...

  m = -3/1 = -3

One of the points we just used is the point where the line crosses the y-axis, at the y-intercept of -1. So, with slope -3 and y-intercept -1, the equation of the line is ...

  y = mx +b . . . . . . slope m and y-intercept b

  y = -3x -1

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On the first day of travel, a driver was going at a speed of 40 mph. The next day, he increased the speed to 60 mph. If he drove
gogolik [260]

Velocity, distance and time:

This question is solved using the following formula:

v = \frac{d}{t}

In which v is the velocity, d is the distance, and t is the time.

On the first day of travel, a driver was going at a speed of 40 mph.

Time t_1, distance of d_1, v = 40. So

v = \frac{d}{t}

40 = \frac{d_1}{t_1}

The next day, he increased the speed to 60 mph. If he drove 2 more hours on the first day and traveled 20 more miles

On the second day, the velocity is v = 60.

On the first day, he drove 2 more hours, which means that for the second day, the time is: t_1 - 2

On the first day, he traveled 20 more miles, which means that for the second day, the distance is: d_1 - 20

Thus

v = \frac{d}{t}

60 = \frac{d_1 - 20}{t_1 - 2}

System of equations:

Now, from the two equations, a system of equations can be built. So

40 = \frac{d_1}{t_1}

60 = \frac{d_1 - 20}{t_1 - 2}

Find the total distance traveled in the two days:

We solve the system of equation for d_1, which gets the distance on the first day. The distance on the second day is d_2 = d_1 - 20, and the total distance is:

T = d_1 + d_2 = d_1 + d_1 - 20 = 2d_1 - 20

From the first equation:

d_1 = 40t_1

t_1 = \frac{d_1}{40}

Replacing in the second equation:

60 = \frac{d_1 - 20}{t_1 - 2}

d_1 - 20 = 60t_1 - 120

d_1 - 20 = 60\frac{d_1}{40} - 120

d_1 = \frac{3d_1}{2} - 100

d_1 - \frac{3d_1}{2} = -100

-\frac{d_1}{2} = -100

\frac{d_1}{2} = 100

d_1 = 200

Thus, the total distance is:

T = 2d_1 - 20 = 2(200) - 20 = 400 - 20 = 380

The total distance traveled in two days was of 380 miles.

For the relation between velocity, distance and time, you can take a look here: brainly.com/question/14307500

3 0
3 years ago
3y+3 (1-y)-y=-6PLEASE help
Murrr4er [49]
3y+4+3y-y=-6
6y-y+4=-6
5y+4=-6
5y=-10
y=-2
If you have any questions let me know
7 0
4 years ago
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