Answer:
Step-by-step explanation:
Considering the function:
The independent variable is "x" and we are asked to model it in terms of the variable "y":
Then, in order to solve for x (which resides in the exponent), we need to use the logarithm function.
Since the base of the exponent is 1.5, we need to use the logarithm base 1.5, to lower that exponent "x":
Answer:
you didn't link a picture
Step-by-step explanation:
dm me the picture and ill do it for you
Answer:
the y value equals 5
Step-by-step explanation:
(x,y)so
plug in 8 for x
5(8)=40
40 -2y=30
subtract 40 from both sides
-2y=-10
divide by -2
y=5
Domain and Range both are real numbers for all odd-degree polynomial functions.
Writing in an Interval Form, note that we use the least value in the left and the most value in the right.
From [a,b], [a,b), (a,b] or (a,b) | a must be less than b.
Therefore, the D choice is wrong in Interval part (However, right in range and domain but just for interval order.)
So the answer is C.
Answer: 3,4,5
Step-by-step explanation: a squared + b squared = c squared
A -> 3 squared is 9
B -> 4 squared is 16
9+16 is 25, so C has to be 25
C -> 5 squared is 25
So 3, 4, 5
