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9966 [12]
2 years ago
11

Math Please help me

Mathematics
1 answer:
erik [133]2 years ago
6 0

Answer:

Input    Output

-3                -9

2                  6

1                   3

0                  0

5                  15

-1                  -3

7                  21

3                  9

10                30

-4                 16

1/2                1.5

Step-by-step explanation: Just multiply everything by 3 I think, please tell me if I am wrong

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Please please help me
enyata [817]

The area of a parallelogram is given by

A=bh

Now, if we consider the 9.9 inches side as the base, then the height is the one labeled with 5.5 inches.

If instead we choose the 11 inches side as the base, the height is h.

So, we can express the area in this two equivalent ways:

A = 9.9\cdot 5.5 = 11\cdot h

Solving for h, we have

h = \dfrac{9.9\cdot 5.5}{11} = 4.95

8 0
3 years ago
24 percent of the swim team members are new on the team. how many members are new?
SpyIntel [72]

Answer:

24/100 x 25 =6

Step-by-step explanation:

6 0
3 years ago
I didn’t study and it’s 2 am pls help
AlexFokin [52]

Answer: 7. g = -50, 8. f= 340/6 9. 3 10 .125

Step-by-step explanation:#7 g(3): 4(3)^2 +6 =12^2 +6 = 1444=6= 150. We divide 150 by 3 giving us -50.  #8We start by putting f(6): -3(6)^2 -4(6) +8. We use PEMDAS. -18^2 -24 +8 = _324-24+8 F= 340/6 #9 g(15) = Square root of 15-6=9 and the square root of 9 is 3, therefore, the answer is 3. #10 h (x) = 2^x we plug -3 to 2^-3. It is a negative number and it gives us .125 or 12.5

3 0
3 years ago
Read 2 more answers
Cory made 4,500 g of candy. He saved 1 kg to eat later. He divided the rest of the candy over 7 bowls to
Olenka [21]

Answer: 500 g of candy in each bowl

Step-by-step explanation:

1,000 g = 1Kg

4,500 g - 1,000 g =  3,500 g of candy were divided over 7 bowls:

Each bowl contains = 3,500 g➗7 bowls = 500 g candy/bowl

Answer: 500 g of candy in each bowl

<h2><em>Spymore</em></h2>
4 0
3 years ago
Last two!!(ty for all the help) :
malfutka [58]
With the b2+b- 12 your gonna want to do this
b2+b-12
b2+4b-3b-12
which is the sum product
after doing that you wanna common the factors from the two pairs. Which is b2+4b-3b-12 then you do you parentheses around b(b+4)-3(b+4) just like that after you do that then you rewrite it in factored form b(b+4)-3(b+4) you then want to rewrite it to this (b-3)(b+4) after that your solution will be (b-3)(b+4) for the first one.
7 0
2 years ago
Read 2 more answers
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