fe (s) + s (l) --> fes (s) in the experiment above, 7.62 g of fe are allowed to react with 8.67 g of s.how much fes is formed
?
1 answer:
Answer:
16.29g
Acc to law of conservation of mass
MASS OF REACTANT = MASS OF PRODUCT SIDE
m (fe) + m(s) = m(fes)
7.62 + 8.67 = m(FeS)
16.29g = m (FeS)
MARK ME AS BRAINLIEST. .☺
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