The solution to the system of equations is (3,1)
Step-by-step explanation:
The system of equations represented by graph are:
![y=4-x\\y=x-2](https://tex.z-dn.net/?f=y%3D4-x%5C%5Cy%3Dx-2)
Solving the system of equations
Let:
![y=4-x\,\,\,eq(1)\\y=x-2\,\,\,eq(2)](https://tex.z-dn.net/?f=y%3D4-x%5C%2C%5C%2C%5C%2Ceq%281%29%5C%5Cy%3Dx-2%5C%2C%5C%2C%5C%2Ceq%282%29)
Putting value of y from eq(2) into eq(1):
![x-2=4-x\\Simplifying:\\x+x=4+2\\2x=6\\x=6/2\\x=3](https://tex.z-dn.net/?f=x-2%3D4-x%5C%5CSimplifying%3A%5C%5Cx%2Bx%3D4%2B2%5C%5C2x%3D6%5C%5Cx%3D6%2F2%5C%5Cx%3D3)
So, Value of x = 3
Putting value of x into eq(2)
![y=x-2\\y=3-2\\y=1](https://tex.z-dn.net/?f=y%3Dx-2%5C%5Cy%3D3-2%5C%5Cy%3D1)
So, value of y= 1
So, The solution to the system of equations is (3,1)
Keywords: System of equations
Learn more about system of equations at:
#learnwithBrainly
Answer:
xy=8
Step-by-step explanation:
The equation for inverse variation is
xy = k where k is the constant of variation
4*2 = k
8=k
The equation is
xy=8
Just remember that 1 mile is equal to 5,280 feet.
If we have 5 miles, we need to multiply it my 5,280 which would equal 26,400.
Then we have the other 529 feet that they gave. Just add 26,400ft and 529ft and they will equal 26,929 ft.
Hope it helped! Remember, five tomatoes! (five two eight oh(0)).
Answer:
width = 2.5 feet
Step-by-step explanation:
Suzanne has a rectangular garden which is 18 feet long and 11 feet wide.
Area of the garden = length times width = 18 times 11= 198 square foot
Let 'w' be the width of the border
Length of the garden with border = 18+2w
Width of the garden with border = 11+2w
Area of the garden with border = ![(18+2w)(11+2w)=4w^2+58w+198](https://tex.z-dn.net/?f=%2818%2B2w%29%2811%2B2w%29%3D4w%5E2%2B58w%2B198)
Area of the border = ![4w^2+58w+198-198=4w^2+58w](https://tex.z-dn.net/?f=4w%5E2%2B58w%2B198-198%3D4w%5E2%2B58w)
She has 168 square foot of paving stones,
![4w^2+58w=168](https://tex.z-dn.net/?f=4w%5E2%2B58w%3D168)
Solve for w
apply quadratic formula
a= 4, b= 58 and c=-168
![\quad x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=%5Cquad%20x%3D%5Cfrac%7B-b%5Cpm%20%5Csqrt%7Bb%5E2-4ac%7D%7D%7B2a%7D)
![w=\frac{-58+-\sqrt{58^2-4\cdot \:4\left(-168\right)}}{2\cdot \:4}](https://tex.z-dn.net/?f=w%3D%5Cfrac%7B-58%2B-%5Csqrt%7B58%5E2-4%5Ccdot%20%5C%3A4%5Cleft%28-168%5Cright%29%7D%7D%7B2%5Ccdot%20%5C%3A4%7D)
![w=\frac{-58+-\sqrt{6052}}{8}](https://tex.z-dn.net/?f=w%3D%5Cfrac%7B-58%2B-%5Csqrt%7B6052%7D%7D%7B8%7D)
we get two values for w
![w=\frac{-58+\sqrt{6052}}{8}=2.47](https://tex.z-dn.net/?f=w%3D%5Cfrac%7B-58%2B%5Csqrt%7B6052%7D%7D%7B8%7D%3D2.47)
![w=\frac{-58-\sqrt{6052}}{8}=-16.97](https://tex.z-dn.net/?f=w%3D%5Cfrac%7B-58-%5Csqrt%7B6052%7D%7D%7B8%7D%3D-16.97)
Answer: q >-6
Step-by-step explanation: