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posledela
2 years ago
5

NEED THIS PLS HELP!!!!!!

Mathematics
2 answers:
erastovalidia [21]2 years ago
8 0

Answer:

x = 7 , y = 37

Step-by-step explanation:

For Δ LMN ≅ Δ PQR

Then corresponding angles must be congruent, that is

∠ P = ∠ L , substitute values

9x - 18 = 5x + 10 ( subtract 5x from both sides )

4x - 18 = 10 ( add 18 to both sides )

4x = 28 ( divide both sides by 4 )

x = 7

Then

∠ P = 9x - 18 = 9(7) - 18 = 63 - 18 = 45°

∠ R = 180° - (84 + 45)° ← sum of angles in a triangle = 180°

∠ R = 180° - 129° = 51°

Then ∠ N = ∠ R

2x + y = 51

2(7) + y = 51

14 + y = 51 ( subtract 14 from both sides )

y = 37

RoseWind [281]2 years ago
6 0

Answer:

x=7

y=37

Step-by-step explanation:

So if the angle of Q=M we can assume that P=L and N=R. Since we don't have the equation for R let's start with P and L.

If P=L that means that (5x+10)=(9x-18) from there we can subtract 5x which makes it so that (10)=(4x-18) from there we can add 18 to each side so we have 28=4x from there we simply divide both sides by 4 which gives us x=7° we can then check that this is correct by doing 5*7+10 which gives us 45° for L and then 9*7-18 which gives us 45° for P

Since we know that the sum of the interior angles of all triangles has to be 180° that means that we can figure out the angle of N and R by doing 180-(84+45) which is 51. Assuming that N=51° we can write something like (2)(7)+y=51 which can be simplified into 14+y=51, then you remove the 14 by subtracting it from both sides which leaves y=37. Once again we have to double-check so (2)(7)+37=N and 2*7=14 so 14+37 obviously equals 51.

I hope this helped. If it did, feel free to mark my answer as brainliest! :)

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Denote the events as follows:

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Compute the probability that at least one of these components will need repair within 1 year as follows:

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Thus, the probability that at least one of these components will need repair within 1 year is 0.0278.

(b)

Compute the probability that exactly one of these component will need repair within 1 year as follows:

P (Exactly 1 component needs repair)

= P (A or B or C)

=P(A\cap B^{c}\cap C^{c})+P(A^{c}\cap B\cap C^{c})+P(A^{c}\cap B^{c}\cap C)\\=[0.02\times (1-0.007)\times (1-0.001)]+[(1-0.02)\times 0.007\times (1-0.001)]\\+[(1-0.02)\times (1-0.007)\times 0.001]\\=0.02766642\\\approx 0.0277

Thus, the probability that exactly one of these component will need repair within 1 year is 0.0277.

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