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iogann1982 [59]
3 years ago
14

Kenneth got a pay check for $415 this week. He made 3.2% commission on total sales. What were his total sales? $12,968.75 $14,52

3.22 $18,422.56 $20,232.85
Mathematics
1 answer:
marta [7]3 years ago
6 0

The total sales of Kenneth is $ 12968.75

<h3><u>Solution:</u></h3>

Given that Kenneth got a pay check for $415 this week

He made 3.2% commission on total sales

To find: total sales of Kenneth

Let "t" be the total sales of Kenneth

Kenneth got a pay check for $415 this week and made 3.2% commission on total sales. Which means that 3.2 % of total sales has yielded $ 415

$ 415 = 3.2% of total sales

415 = 3.2% of t

415 = \frac{3.2}{100} \times t\\\\415 = 0.032 \times t\\\\t = \frac{415}{0.032}\\\\t = 12968.75

Thus the total sales is $ 12968.75

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Answer:

c.A 90% confidence level and a sample size of 300 subjects.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level 1-\alpha, we have the confidence interval with a margin of error of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

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In this problem

The proportions are the same for all the options, so we are going to write our margins of error as functions of \sqrt{\pi(1-\pi)}

So

a.A 99% confidence level and a sample size of 50 subjects.

n = 50

99% confidence interval

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

The margin of error is

M = z\sqrt{\frac{\pi(1-\pi)}{n}} = \frac{2.575}{\sqrt{50}}\sqrt{\pi(1-\pi)} = 0.3642\sqrt{\pi(1-\pi)}

b.A 90% confidence level and a sample size of 50 subjects.

n = 50

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The margin of error is

M = z\sqrt{\frac{\pi(1-\pi)}{n}} = \frac{1.645}{\sqrt{50}}\sqrt{\pi(1-\pi)} = 0.2623\sqrt{\pi(1-\pi)}

c.A 90% confidence level and a sample size of 300 subjects.

n = 300

90% confidence interval

So \alpha = 0.1, z is the value of Z that has a pvalue of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

The margin of error is

M = z\sqrt{\frac{\pi(1-\pi)}{n}} = \frac{1.645}{\sqrt{300}}\sqrt{\pi(1-\pi)} = 0.0950\sqrt{\pi(1-\pi)}

This produces smallest margin of error.

d.A 99% confidence level and a sample size of 300 subjects.

n = 300

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So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

The margin of error is

M = z\sqrt{\frac{\pi(1-\pi)}{n}} = \frac{2.575}{\sqrt{300}}\sqrt{\pi(1-\pi)} = 0.1487\sqrt{\pi(1-\pi)}

6 0
4 years ago
Four times a number, decreased by eight equals twelve. What is the number?
AleksandrR [38]

Let the number be x.

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6 0
3 years ago
Jacob wants to buy a $500,000 15-year term life policy, and the annual premium rate (per $1000 of face value) for his age group
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If Jacob lives until the end of the term of his policy, the total amount he would have paid in premiums overall is $50,850.

<h3>How much would he have paid in premiums?</h3>

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To learn more about division, please check: brainly.com/question/194007

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Answer:

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