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omeli [17]
3 years ago
13

Lexi2984 can u help me with this question

Mathematics
1 answer:
arsen [322]3 years ago
7 0

9514 1404 393

Answer:

  see the attachment

Step-by-step explanation:

The x- and y-intercepts are easily found:

<u><em>X-intercept</em></u>

Set y = 0 and divide by the coefficient of x.

  -x +0 = 8

  x = -8

__

<u><em>Y-intercept</em></u>

Set x = 0 and divide by the coefficient of y.

  0 -2y = 8

  y = -4

__

Now, we have two points on the graph: (-8, 0) and (0, -4). A third point can be one that is halfway between these: (-4, -2). The graph is attached.

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MatroZZZ [7]

Answer:

it's D

Step-by-step explanation:

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5 0
3 years ago
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Please help anyone and thank you
snow_lady [41]

Answer and Step-by-step explanation:

The two statements that are true are statement 1 and statement 4:

- The sum of pi and 0 is irrational.

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2 years ago
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NARA [144]

Answer:

Below.

Step-by-step explanation:

f) (a + b)^3 - 4(a + b)^2  

The (a+ b)^2 can be taken out to give:

= (a + b)^2(a + b - 4)

= (a + b)(a + b)(a + b - 4).

g)  3x(x - y) - 6(-x + y)

=  3x( x - y) + 6(x - y)

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= 3(x + 2)(x - y).

h) (6a - 5b)(c - d) + (3a + 4b)(d - c)

=  (6a - 5b)(c - d) + (-3a - 4b)(c - d)

= -(c - d)(6a - 5b)(3a + 4b).

i)  -3d(-9a - 2b) + 2c (9a + 2b)

= 3d(9a + 2b) + 2c (9a + 2b)

=  3d(9a + 2b) + 2c (9a + 2b).

= (3d + 2c)(9a + 2b).

j)  a^2b^3(2a + 1) - 6ab^2(-1 - 2a)

=  a^2b^3(2a + 1) + 6ab^2(2a + 1)

= (2a + 1)( a^2b^3 + 6ab^2)

The GCF of a^2b^3 and  6ab^2 is ab^2, so we have:

(2a + 1)ab^2(ab + 6)

= ab^2(ab + 6)(2a + 1).

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