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3 years ago

Lexi2984 can u help me with this question

Mathematics

1 answer:

arsen [322]3 years ago

7 0

9514 1404 393

Answer:

see the attachment

Step-by-step explanation:

The x- and y-intercepts are easily found:

X-intercept

Set y = 0 and divide by the coefficient of x.

-x +0 = 8

x = -8

Y-intercept

Set x = 0 and divide by the coefficient of y.

0 -2y = 8

y = -4

Now, we have two points on the graph: (-8, 0) and (0, -4). A third point can be one that is halfway between these: (-4, -2). The graph is attached.

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A research paper requires you to organize your paper in a particular way and follow a specific form.

OleMash [197]

Awnser:
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3 years ago

Read 2 more answers

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Mars2501 [29]

1165 divided by 255 = 5.17 = 5 costumes

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3 years ago

Pls helppppppppppp i give points

d1i1m1o1n [39]

The answer you selected in that photo given, is correct. I can tell just by using common sense and by judging the other options second option (B) is looking the most clearest one to me.

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2 years ago

Jill is designing a picture frame for an art project. She plans to have a square piece of glass (x inches by x inches) in the ce

ra1l [238]

How would I at least start out those two problems?

It looks to me like you already did. Now just follow through with it.

If the length of each side of the frame's inner dimension (i.e. the glass) is x, and the length of each side of the frame's outer dimension is x^2 - 3, then the area of the frame is:

A = (outer dimension)^2 - (inner dimension)^2
27 = (x^2 - 3)^2 - (x)^2
27 = x^4 - 6x^2 + 9 - x^2
27 = x^4 - 7x^2 + 9 <----- This is where you got to already.
0 = x^4 - 7x^2 - 18
0 = (x^2 - 9)(x^2 + 2)

Therefore, either x^2 = 9 or x^2 = -2... and you know it can't be the latter.
Thus, x^2 = 9 and therefore x = 3. The glass is 3" on each side.

Each (outer) side of the frame is x^2 - 3 = 9 - 3 = 6"

4 0

3 years ago

If a sequence c1,c2,c3,...has limit K then the sequence ec1,ec2,ec3,...has limit e^K. Use this fact together with l'Hopital's ru

aleksandrvk [35]

Answer:

Step-by-step explanation:

If a sequence c1,c2,c3,...has limit K then the sequence ec1,ec2,ec3,...has limit e^K. Use this fact together with l'Hopital's rule to compute the limit of the sequence given by

bn=(n)^(5.6/n).

$L = \lim_{n \to \infty} b_n \\\\\\L= \lim_{n \to \infty} n^{\frac{5.6}{n} }$

Log on both sides

$In (L) = \lim_{n \to \infty} In (n)^{\frac{5.6}{n} }\\\\= \lim_{n \to \infty} \frac{5.6}{n} In(n)$

$=5.6 \lim_{n \to \infty} \frac{d}{dn} In(n)/\frac{d}{dn} (n)\\\\=5.6 \lim_{n \to \infty} \frac{1}{n} /1 \\\\=5.6 \lim_{n \to \infty} \frac{1}{n} \\\\=5.6 \times 0\\\\In(L) =0\\\\L=e^0\\\\L=1$

$\therefore \lim_{n \to \infty} (n)^{\frac{5.6}{n} =1$

5 0

3 years ago