Ask question

Ask question

All categories

kakasveta [241]

4 years ago

14

What are two features of any density curve

2 answers:

Aleksandr [31]4 years ago

3 0

1. the total of an area under the curve must be equal to one. 2. Every point of the curve must have an vertical height that is 0 or greater.

Alex_Xolod [135]4 years ago

3 0

Step-by-step explanation:

1. The area under the curve adds up to 1.0, because the sum of probabilities in all situations/events is 1.0.

2. The domain is (-infinity, +infinity). The impossible events are given a probability of zero, if applicable.

You might be interested in

A machine laying underground cable can place 125 meters of cable in 5 minutes.What is the rate per minute?

kaheart [24]

Answer:

25 m of cable per minute

Step-by-step explanation:

The unit rate is:

125 m of cable

---------------------- = 25 m of cable per minute

5 minutes

7 0

3 years ago

How much of a spice that is 3% salt should be added to 175 ounces of a spice that is 6% salt in order to make a spice that is 5%

Nonamiya [84]

Answer:

Let y represents the ounces of first spice.

From the given statements, we draw a table as shown below:

ounces of spice Percentage ounces of salt

First spice y 3% 0.03x

Second spice 175 6% 175(0.06)

Final mixture y + 175 5% (x+15)(0.05)

Now, to solve for y

we have;

Final spice = First spice + second spice

$0.03y + 175(0.06) = (y+175)(0.05)$

$0.03y+ 10.5= 0.05y+ 8.75$

Subtract 10.5 on both sides we have;

$0.03y+ 10.5 -10.5= 0.05y+ 8.75 -10.5$

Simplify:

$0.03y = 0.05y -1.75$

Subtract 0.05y on both sides

$0.03y -0.05y= 0.05y -1.75-0.05y$

Simplify:

$-0.02y = -1.75$

Divide both sides by -0.02, we get;

$y = \frac{-1.75}{-0.02} = 87.5$

Therefore, 87.5 ounces of spices that is 3% salt should be added to 175 ounces of a spice that is 6% salt in order to make a spice that is 5% salt

5 0

3 years ago

Read 2 more answers

10 is 70% of what number? If necessary, round to the nearest tenth.

Sergio [31]

Answer:

The required answer is 7.

Step-by-step explanation:

=10*70/100

=7

5 0

3 years ago

Read 2 more answers

A line has a slope of 5 and a y-intercept of 0. Which is the equation of the line?

tangare [24]

The answer is B) y= 5x

7 0

3 years ago

The quadratic equation 8x²+12x-14 has two real roots. What is the sum of the squares of these roots?

mars1129 [50]

Answer:

The real roots are

$x=\frac{(-3+\sqrt{37})}{4}$ and $x=\frac{(-3-\sqrt{37})}{4}$

The sum of the squares of these roots is $\frac{-3}{2}$

Step-by-step explanation:

The given quadratic equation is $8x^2+12x-14$ has two real roots.

To find the roots .

$8x^2+12x-14=0$

Dividing the above equation by 2

$\frac{1}{2}(8x^2+12x-14)=\frac{0}{2}$

$4x^2+6x-7=0$

For quadratic equation $ax^2+bx+c=0$ the solution is $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Where a and b are coefficents of $x^2$ and x respectively, c is a constant.

For given quadratic equation

a=4, b=6, c=-7

$x=\frac{-6\pm\sqrt{6^2-4(4)(-7)}}{2(4)}$

$=\frac{-6\pm\sqrt{36+112}}{8}$

$=\frac{-6\pm\sqrt{148}}{8}$

$=\frac{-6\pm\sqrt{37\times 4}}{8}$

$=\frac{-6\pm\sqrt{37}\times\sqrt{4}}{8}$

$=\frac{-6\pm\sqrt{37}\times 2}{8}$

$=2\frac{(-3\pm\sqrt{37})}{8}$

$=\frac{-3\pm\sqrt{37}}{4}$

$x=\frac{(-3\pm\sqrt{37})}{4}$

The real roots are

$x=\frac{(-3+\sqrt{37})}{4}$ and $x=\frac{(-3-\sqrt{37})}{4}$

Now to find the sum of the squares of these roots

$\left[\frac{-3+\sqrt{37}}{4}+\frac{(-3-\sqrt{37})}{4}\right]^2=\frac{-3+\sqrt{37}-3-\sqrt{37}}{4}$

$=\frac{-6}{4}$

$=\frac{-3}{2}$

$\left[\frac{-3+\sqrt{37}}{4}+\frac{(-3-\sqrt{37})}{4}\right]^2=\frac{-3}{2}$

Therefore the sum of the squares of these roots is $\frac{-3}{2}$

3 0

3 years ago