F(-3) = 8
Plug -3 into x and just solve it.
Maria = x
Tom = y
Use substitution
x+y=30
2y=x
2y+y=30
3y=30
y=10
Tom is 10 years old.
x+y=30
x+10=30
x=20
Maria is 20 years old.
Answer:
Ok, we have a system of equations:
6*x + 3*y = 6*x*y
2*x + 4*y = 5*x*y
First, we want to isolate one of the variables,
As we have almost the same expression (x*y) in the right side of both equations, we can see the quotient between the two equations:
(6*x + 3*y)/(2*x + 4*y) = 6/5
now we isolate one off the variables:
6*x + 3*y = (6/5)*(2*x + 4*y) = (12/5)*x + (24/5)*y
x*(6 - 12/5) = y*(24/5 - 3)
x = y*(24/5 - 3)/(6 - 12/5) = 0.5*y
Now we can replace it in the first equation:
6*x + 3*y = 6*x*y
6*(0.5*y) + 3*y = 6*(0.5*y)*y
3*y + 3*y = 3*y^2
3*y^2 - 6*y = 0
Now we can find the solutions of that quadratic equation as:

So we have two solutions
y = 0
y = 2.
Suppose that we select the solution y = 0
Then, using one of the equations we can find the value of x:
2*x + 4*0 = 5*x*0
2*x = 0
x = 0
(0, 0) is a solution
if we select the other solution, y = 2.
2*x + 4*2 = 5*x*2
2*x + 8 = 10*x
8 = (10 - 2)*x = 8x
x = 1.
(1, 2) is other solution
Answer:
13
Step-by-step explanation:
1710/125 = 13.68
You need
125 x 13 = 1710
A student could take 13 credits.
Answer:
426,120 litros se producen en un día Se producen
12,783,600 litros por mes (para un cálculo de 30 días en un mes)
Step-by-step explanation:
Aquí, debemos calcular la cantidad en litros de petróleo producido en un pozo petrolero.
Se nos dice que se producen 2.680 barriles por día y cada barril contiene 159 litros de petróleo.
La producción diaria en litros es, por lo tanto, de 159 * 2680 = 426,120 litros.
Ahora, para la producción mensual, supongamos que hay 30 días en un mes, la cantidad en litros producidos por mes sería la cantidad diaria multiplicada por la cantidad de días en un mes.
Matemáticamente, eso sería 30 * 426,120 = 12,783,600 litros