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2 years ago

Plz help me well mark brainliest if you are correct!

Mathematics

2 answers:

ludmilkaskok [199]2 years ago

8 0

Answer:

-4

Step-by-step explanation:

First combine 2/3 - 4, the quantity enclosed by absolute value symbols | :

The LCD heree is 3. Thus, 2/3 - 4 can be rewritten as 2/3 - 12/3, or -10/3.

Next, take the absolute value of this -10/3: we get 10/3.

Then we have -10/3 divided by 5/6:

-10

-------

--------------

----

Here we're dividing by a fraction. An equivalent expression involves inverting 5/6 and multiplying the result by -10/3:

-10 6

----- * -----

3 5

This reduces to -2(2), or -4

Luba_88 [7]2 years ago

4 0

The correct answer is -4 I am 100 percent sure of it

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For each of these relations on the set {21, 22, 23, 24}, decide whether it is reflexive, whether it is symmetric, whether it is

bonufazy [111]

Answer:

Step-by-step explanation:

I. { (22,22) , (22,23) , (22,24) , (23,22) , (23,23) , (23,24) }

Reflexive : True because we see the pairs (22,22) , (23,23)..

Symmetrix : NO, as we see the pairs (22,24) BUT NOT (24,22)

Transitive : YES, As we see (22,22 ) and (22, 24) , we see the pairs (22,24)

Antisymmetric : NO

II){ (21,21) , (21,22) , (22,21) , (22,22) , (23,23) , (24,24) }

Reflexive : True because we see the pairs (22,22) , (23,23) (21,21)

Symmetrix : Yes, as we see the pairs (21,22) AND (22,21)

Transitive : YES,

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7 0

3 years ago

Read 2 more answers

2. 4x + 5y = -30 Slope-standard form

Lerok [7]

Y=mx+c is the slope standard form
5y=-30-4x
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7 0

2 years ago

In a small chess tournament, 20 matches were played. Find out how many people were involved if it is known that each participant

Nina [5.8K]

Answer:

5 players participated in the tournament.

Step-by-step explanation:

In a small chess tournament, 20 matches were played.

Let us assume that n number of players participated in the tournament

As in each game 2 players play, so the number of ways they can play is,

$=\ ^nC_2$

As they played 2 games with every other participant in the tournament.

So the total number of games is,

$=\ 2\times ^nC_2$

But it is given to be 20, so

$\Rightarrow \ 2\times ^nC_2=20$

$\Rightarrow \ ^nC_2=10$

$\Rightarrow \dfrac{n!}{2!(n-2)!}=10$

$\Rightarrow \dfrac{n(n-1)}{2}=10$

$\Rightarrow {n(n-1)=20$

As $5\times 4=20$ , so we get n=5.

Therefore, 5 players participated in the tournament.

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2 years ago

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Nastasia [14]

The answer is 6 because you do this

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3 years ago

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Lina20 [59]

It’s the 3rd option!

-5 (the bubble shaded black), the arrow going left towards -9.

Hope this helps!

4 0

2 years ago