weather is like corono everywhere #stay safe
Answer:
The first step is to identify the need and constraints
Explanation:
Answer:
factor of safety = 0.8
Explanation:
given data
maximum gauge pressure in steel p = 10 MPa
outer diameter do = 200 mm
wall thickness t = 2 mm
ultimate stress of the steel σU = 400 MPa
solution
We check the type of shell that is
so we can see that that is
so that it mean vessel is a thin shell now we can we get maximum pressure by the maximum tensile stress is
σ = .......................1
put here value and we get
σ =
σ = 500 MPa
so factor of safety will be express as
factor of safety = ..........2
factor of safety =
factor of safety = 0.8
Answer:
e = 3.97*10^-4
Explanation:
1.8 mm = 0.0018 m
2.6*10^4 mm = 26 m
Elongation is The ratio between the stretched length and the original length.
e = L/L0
This is calculated with Hooke's law:
e = σ/E
Where
σ: normal stress
E: elastic constant
σ = P/A
Where
P: normal load
A: cross section
A = π/4 * d^2
Therefore:
e = P / (A * E)
e = 4 * P / (π * d^2 * E)
e = 4 * 290 / (π * 0.0018^2 * 207*10^9) = 3.97*10^-4
To develop the problem it is necessary to apply the concepts of Volume calculation, area calculation and the solidification time.
The solidification time equation is given by
Where,
TST = Total solidification time
V = Volume of the casting
A = Surface area of casting
n = Exponent with typical value=2
= Mold constant
We do not have the volume or area, so we proceed to calculate them with the data we have,
Volume,
Area,
Replacing at the previous equation we have
Therefore it will take the casting to solidify around to 2.13min