The largest radius for the swimming pool is 15.1 feet
Step-by-step explanation:
Step 1:
Circumference of the circular swimming pool built by Dan = 95 feet
We need to determine the largest radius for the pool.
Step 2 :
Circle's circumference is given by 2πr
Where r represents the radius
This shows that the radius is in direct proportion to the circumference. Hence the radius corresponding to the maximum circumference will be the largest possible radius
So we have 2πr = 95
=> r =
=> r = × where
=> r = 15.1 feet (rounded off to tenth of a foot)
Step 3 :
The largest radius for the swimming pool is 15.1 feet
Answer:
Length = 5 feet
Width = 4 feet
Step-by-step explanation:
Perimeter of the sandbox = 18 feet
Perimeter of a rectangle = 2(length + width)
the length of the sandbox is one foot longer than the width
Let
Width = x
length = x + 1
Perimeter of a rectangle = 2(length + width)
18 = 2{(x+1) + x}
18 = 2{x + 1 + x)
18 = 2(2x + 1)
18 = 4x + 2
4x = 18 - 2
4x = 16
Divide both sides by 4
x = 16/4
= 4
Width = x = 4 feet
length = x + 1
= 4 + 1
= 5 feet
Answer:
3/8 + 1 1/4 equals to <u><em>1.625</em></u>
Step-by-step explanation:
Answer:
254m
Step-by-step explanation:
The setup will be in form of a right triangle. Hence;
The angle of elevation = 64degrees
distance from herself to the base of the castle = 124 meters (Adjacent)
Required
Height of the castle (Opposite)
Using the SOH CAH TOA identity
Tan theta = opp/adj
Tan 64 = H/124
H = 124tan64
H = 124(2.05030)
H = 254.23
H ≈ 254m
Hence the height of the castle to the nearest whole meters is 254metres
90kg
It is just a simple proportional problem. If you subtract 10%, then you subtrat 10 kg.