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3 years ago

Ivan and Kate live 40 miles apart. Ivan leaves his house at 8:00 a.m.

Mathematics

1 answer:

Triss [41]3 years ago

6 0

Answer: Time at which the meet = 10:17:24 am

Step-by-step explanation: Speed of Ivan = 12 mph

Speed of Kate = 16 mph

Total distance traveled = Initial separation = 40 miles

Ivan leaves his house at 8:00 a.m and Kate leaves her house at 9:30 a.m

If t is the time of catch up after Ivan starting, time taken by Kate is t - 1.5,

We have

Distance = Speed x Time

Total distance traveled = Distance traveled by Kate + Distance traveled by Ivan

40 = t x 12 + (t-1.5) x 16

40 = 28t - 24

28t = 64

t = 2.29 hours

So after 2.29 hours of Ivan's starting they meet,

Time = 8:00 am + 2.29 hours = 10:00 am + 0.29 x 60 minutes = 10:17am + 0.4 x 60 seconds = 10:17:24 am

Time at which the meet = 10:17:24 am

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