Question

Ivan and Kate live 40 miles apart. Ivan leaves his house at 8:00 a.m.

Answer 1

Answer: Time at which the meet = 10:17:24 am

Step-by-step explanation: Speed of Ivan = 12 mph

Speed of Kate = 16 mph

Total distance traveled = Initial separation = 40 miles

Ivan leaves his house at 8:00  a.m and Kate leaves her house at 9:30  a.m

If t is the time of catch up after Ivan starting, time taken by Kate is t - 1.5,

We have

            Distance = Speed x Time

         Total distance traveled = Distance traveled by Kate + Distance traveled by Ivan

       40 = t x 12 + (t-1.5) x 16

        40 = 28t - 24

         28t = 64

             t = 2.29 hours

So after 2.29 hours of Ivan's starting they meet,

Time = 8:00 am + 2.29 hours = 10:00 am + 0.29 x 60 minutes = 10:17am + 0.4 x 60 seconds = 10:17:24 am

Time at which the meet = 10:17:24 am