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2 years ago

6x+10=30x+135 solve for "x"

Mathematics

1 answer:

Bezzdna [24]2 years ago

5 0

Answer:

x=-125/24

Step-by-step explanation:

(6x+10)+(-10-30x)=(30x+135)+(-10-30x)

(6x+10)+(-30x-10)=(30x+135)+(-30x-10)

6x+10-30x-10=30x+135-30x-10

6x-30x+10-10=30x-30x+135-10

-24x=125

24x/24=-125/24

x=-125/24

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* WILL GIVE BRAINIEST*

k0ka [10]

Answer:

B: 280

Step-by-step explanation:

The regression line predicts that when x equals 5:

$log_{10}(y) = 2.447$

In order to find the value for y, one must simply apply the following logarithmic property:

if : $log_{b}(a) = c$

then: $b^c = a$

Applying it to this particular problem:

$log_{10}(y) = 2.2447\\10^{2.447}= y\\y=280$

Therefore, the regression line predicts y will equal 280 when x equals 5.

3 0

3 years ago

The length of a rectangle is 3 centimeters less than four times its width. Its area is 10 square centimeters. Find the dimension

Kay [80]

Answer:

W = 2 cm

L = 5 cm

Step-by-step explanation:

A rectangle is a four sided shape with 4 perpendicular angles. It has two pairs of parallel sides which are equal in distance: width and length. Its area, the amount of space inside it, can be found using the formula A = l*w. If the area is 10 cm² and the length is "3 cm less than 4 times the width" or 4w - 3, you can substitute and solve for w.

A = l*w

10 = (4w - 3)(w)

10 = 4w² - 3w

Subtract 10 from both sides to make the equation equal to 0. Then solve the quadratic by quadratic formula.

4w² - 3w - 10 = 0

Substitute a = 4, b = -3 and c = -10.

$w = \frac{3 +/- \sqrt{(-3)^2 - 4(4)(-10)} }{2(4)} = \frac{3 +/- \sqrt{9 +160)} }{8} = \frac{3 +/- \sqrt{169} }{8} = \frac{3+/-13}{8}$

There are two possible solutions which can be found.

3 + 13 / 8 = 16/ 8 = 2

3 - 13 / 8 = -10/8 = -5/4

Since w is a side length or distance, it must be positive so w = 2 cm.

If the width is 2 cm then the length is 4(2) - 3 = 8 - 3 = 5 cm.

8 0

3 years ago

Con

mr Goodwill [35]

Answer:

The coordinates of E are $E(x,y) = \left(\frac{9}{2}, 0 \right)$ .

Step-by-step explanation:

The triangle ABC represents a right triangle as both sides AB and AC are orthogonal to each other. The side AB is in the y axis, whereas the side AC is in the x axis. The triangle is dilated with respect to the origin, in which point A is set.

Vectorially speaking, dilation is defined by the following operation:

$P'(x,y) = O(x,y) + k\cdot [P(x,y) - O(x,y)]$ (1)

Where:

$O(x,y)$ - Point of reference.

$P(x,y)$ - Original point.

$P'(x,y)$ - Dilated point.

$k$ - Dilation factor.

By applying this operation, point B becomes point D:

$B(x,y) = (0,4)$ , $D(x,y) = (0,6)$

$D(x,y) = (0,0) + k\cdot [(0,4)- (0,0)]$

$D(x,y) = (0,0) + k\cdot (0,4)$

$(0,6) = (0,0) +(0,4\cdot k)$

$(0, 6) = (0,4\cdot k)$

$k = \frac{3}{2}$

Lastly, we transform point C into point E by applying the same operation: $C(x,y) = (3, 0)$ , $O(x,y) = (0,0)$ and $k = \frac{3}{2}$

$E(x,y) = (0,0) + \frac{3}{2}\cdot [(3,0)-(0,0)]$

$E(x,y) = \left(\frac{9}{2}, 0 \right)$

The coordinates of E are $E(x,y) = \left(\frac{9}{2}, 0 \right)$ .

8 0

3 years ago

Lyte wishes to study speed of Reaction Time to press a button in response to the onset of a lamp. The independent variable (V) i

Vaselesa [24]

Complete question:

Dr. Lyte wishes to study speed of Reaction Time to press a button in response to the onset of a lamp. The independent variable (V) is the color of the light produced by the lamp (red, orange, yellow, green, or blue) Since only 10 participants are available, she elects to administer the IV within-subjects with all 10 participants being exposed to all five levels of the color variable. The order of the color of the light presentation is to be counterbalanced. Using concepts from the textbook, why would Dr. Lyte need to use counterbalancing in this scenario?

Answer:

Here,

Independent variable (IV) is: the color of the light produced by the lamp (red, orange, yellow, green, or blue)

We are also told only 10 participants are available.

All 10 participants are being exposed to all five levels of the color variable in the same order.

Counterbalancing is said to be a technique used when establishing task order. It helps prevent introduction if cofounding variables.

Dr. Lyte will need to use counterbalancing technique in this scenario because some of the participants may be unable to understand difference in similar colours. Example some participants may not be able to differentiate between orange and red when the red colour comes after orange.

But using counterbalancing technique, Dr. Lyte can avoid such an error.

6 0

4 years ago

Which expression is equivalent to StartRoot 120 x EndRoot?.

Irina-Kira [14]

Here for 120, the expression for the start root and end root is given

$\sqrt{120} =2\sqrt{30}$