The option that are indicators of heatstroke are:
- high temperature above 104F.
- Layer of red skin that can be either dry or moist.
- Throbbing headache.
- Dizziness, vomiting.
- Seizures.
<h3>What is Heat stoke?</h3>
This is known to be a kind of a life-threatening condition that is said to often occurs if a person ignore the warning signs of heat exhaustion or do when a person do not act quickly enough to get care.
Hence, The option that are indicators of heatstroke are:
- high temperature above 104F.
- Layer of red skin that can be either dry or moist.
- Throbbing headache.
- Dizziness, vomiting.
- Seizures.
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To prevent injury while maintaining equipment make sure the equipment is locked out and/or tagged out (i.e., de-energized).
<h3>What does locked-out equipment mean?</h3>
Equipment is locked out when it does not contain any type of change that may affect the security of a device.
This task (locked out) is fundamental to avoid any safety problems associated with a device.
In conclusion, to prevent injury while maintaining equipment make sure the equipment is locked out and/or tagged out (i.e., de-energized).
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Sry can you help me what is 7 3/4% as a fraction in simplest form
The tension on each segment of the clothesline is : 110 N
<u>Given data : </u>
mass of object = 100 n = 10 kg
Horizontal distance of clothesline = 4 m
middle of clothesline sag s by : 1m
<h3 /><h3>Determine the tension on each segment of clothesline</h3>
<u>First step</u> : calculate the horizontal angle made by the sagging
β = arctan ( 1 m / 2m ) ----- ( 1 )
= arctan ( 0.5 )
≈ 26.57°
Note : Tension in th y axis ( Ty ) = Tsinβ
Therefore :
Tension on each segment can be calculated using the formula below
2Tsinβ - mg = 0
solve for T
T = mg / 2sinβ
= ( 10 * 9.8 ) / 2 * sin 26.57°
= 98 / 0.89
= 110 N
Hence we can conclude that the tension on each segment of the clothesline is : 110 N
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What am I supposed to do with these numbers?
