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Assoli18 [71]
3 years ago
12

What is the equation of the line that passes through the point (6, 3) and has a slope of - 2/3 ?

Mathematics
1 answer:
Airida [17]3 years ago
3 0

Answer:

Therefore, the equation of a line passing through (6,−3) having slope 23 is y−(−3)=23(x−6)or3(y+3)=2(x−6)or2x−3y=21 .

Step-by-step explanation:

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if you've read those links already, you'd know what we're doing here.

we'll move the repeating part to the left-side of the dot, by multiplying by "1" and as many zeros as needed, or 10 at some power pretty much.

on 0.13 we need 100 to get 13.13.... and on 0.1234, we need 10000 to get 1234.1234....


\bf 0.\overline{13}~\hspace{10em}x=0.\overline{13}
\\\\[-0.35em]
~\dotfill\\\\
\begin{array}{|lll|ll}
\cline{1-3}
&&\\
100\cdot 0.\overline{13}& = & 13.\overline{13}\\
100\cdot x&& 13 + 0.\overline{13}\\
100x&&13+x
\\&&\\
\cline{1-3}
\end{array}\implies \begin{array}{llll}
100x=13+x\implies 99x=13
\\\\
x=\cfrac{13}{99}
\end{array}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
0.\overline{1234}~\hspace{10em}x=0.\overline{1234}
\\\\[-0.35em]
~\dotfill


\bf \begin{array}{|ccc|ll}
\cline{1-3}
&&\\
10000\cdot 0.\overline{1234}&=&1234.\overline{1234}\\
10000\cdot x&=&1234+0.\overline{1234}\\
10000x&=&1234+x
\\&&\\
\cline{1-3}
\end{array}\implies \begin{array}{llll}
10000x=1234+x
\\\\
9999x=1234\implies x=\cfrac{1234}{9999}
\end{array}

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hope this helps

brainliest appreciated

good luck! have a nice day!

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