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abruzzese [7]
3 years ago
7

If software can be affected by viruses, what do you think hardware can be affected by

SAT
1 answer:
KengaRu [80]3 years ago
5 0

Answer:

An easy way for a virus to damage hardware is by disrupting the normal operation of a computer’s power management or thermal management. For instance, the fans in laptops can be controlled through software. Disabling the fans can destroy the computer.

Explanation:

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An air pump does 5,600 J of work to launch a water bottle rocket into the air. If the air pump applies 150 N of force to the roc
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Answer:5.3*10^1

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which of the following statements best explains how the membranes in winter wheat are able to remain fluid in extremely cold tem
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Membrane fluidity is a measurement of the viscosity of the lipid bilayer. The factors that affect membrane fluidity are temperature, double bonds of unsaturated phospholipids, and the amount of cholesterol.

  • The membranes in winter wheat are able to remain fluid in extremely cold temperatures because they contain an increased proportion of UNSATURATED PHOSPHOLIPIDS.

  • Unsaturated fatty acids that form phospholipids have at least one double bond, maintaining thus bilayer fluidity by reducing the packing between phospholipids.

  • As temperature increases, membrane fluidity increases because it decreases intermolecular interactions between components of the lipid bilayer.

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6 0
2 years ago
1. The word “devouring” is used in paragraph 1. What is the effect of this word choice on the mood (emotional atmosphere) of the
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Answer:

The word 'devouring' immediately establishes a mood of unease as that word shows that something is not right.  

Explanation:

7 0
3 years ago
Two small metal cubes with masses 2. 0 g and 4. 0 g are tied together by a 5. 0-cm-long massless string and are at rest on a fri
Aleks04 [339]

The energy of the system, tension in the string, and speed of each cube are respectively; U = 0.72 J, T = 14 N and (V₂, V₄) = (-22, 14)

<h3>Calculation of energy and tension in a String</h3>

We are given;

Mass of cube 1; m₁ = 2 g

Mass of cube 2; m₂ = 4 g

Distance between cubes; d = 5 cm = 0.05 m

Charges of cubes; Q = q = +2. 0 μc = 2.0 × 10⁻⁶ C

A) Formula for the energy of the system is;

U = kQq/d

U = 8.99 × 10⁹ × (2.0 × 10⁻⁶ C)²/0.05 m

U = 0.03596/0.05

U = 0.72 J

B) Formula for the Tension is;

T = U/d

T = 0.72/0.05

T ≈ 14 N

C) Momentum is conserved, and as such the initial momentum is zero. Thus;

0 = (0.0020 × V₂) + (0.0040 × V₄)

⇒ V₂ = -2V₄

Energy is also conserved and so;

(½ × 0.0020 × (-2V₄)²) + (½ × 0.004 × (V₄)²) = 0.72 J

-0.0040V₄² + 0.002V₄² = 0.72 J

0.0060V₄² = 0.72 J

V₄² = 0.72/0.0060

V₄² = 120

V₄ = √120

V₄ ≈ 11 m/s

Recall that; V₂ = -2V₄

Thus;

V₂ = -2(11) m/s

V₂ = -22 m/s

Thus;

(V₂, V₄) = (-22, 14)

Read more about Conservation of Momentum at; brainly.com/question/7538238

8 0
3 years ago
How many reports for colleges does the ACT refrigeration fee cover
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4 reports

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