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suter [353]
2 years ago
9

GIVING BRAINLIEST! PLEASE HELP!

Mathematics
1 answer:
love history [14]2 years ago
3 0

Answer:

Below

Step-by-step explanation:

When we are talking about domain it is basically asking "are there any restrictions on the x's?". And range is basically asking "are there any restrictions on the y's?" So :

a) We can see that this graph extends from -3 to 3

Domain : { XeR | -3 < x < 3 }

Range : { YeR | -2 < y < 3 }

b) Because this graph has arrows, we know that the x and y coordinates will be infinite

Domain : { XeR }

Range : { YeR }

c) We can see that this graph extends from 0 - 4

Domain : { XeR | 0 < x < 4 }

Range : { YeR | -4 < y < 1 }

     * make sure you put a little dash under the < signs because they can be equal to these values as well! I didn't have the symbol unfortunately

Hope this helps! Best of luck <3

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What is the interquartile range of the data set?
anastassius [24]

The interquartile range of the data set will be 30.

<u><em>Explanation</em></u>

Given data set: { 40, 48, 62, 60, 62, 40, 25, 50, 20, 30, 55 }

First we will rearrange the data in numeric order. So...

{ 20, 25, <u><em>30</em></u>, 40, 40, 48, 50, 55, <u><em>60</em></u>, 62, 62 }

Here the middle value in the set is 48. So, the median is 48 and it is diving the whole set into two different data sets. The median of the first set is 30 and median of the second set is 60.

That means, Lower quartile(Q₁) = 30 and Upper quartile(Q₃) = 60

So, the interquartile range of the data set: IQR= Q₃ - Q₁ = 60 - 30 = 30




6 0
3 years ago
Player II is moving an important item in one of three cars, labeled 1, 2, and 3. Player I will drop a bomb on one of the cars of
Serhud [2]

Answer:

There are 3 strategies for Player I - i) throw bomb on car 1 ii) i) throw bomb on car 2 iii) i) throw bomb on car 3

Similarly, there are 3 strategies for Player II - i) put item on car 1 ii) put item on car 2 iii) put item on car 3

The payoff matrix is \begin{pmatrix} 3/4 &0 &0 \\ 0&1/4 &0 \\ 0&0 &1/2 \end{pmatrix}

Row 1, Column 1 : If the player I drops bomb on car 1 and the item is in the car 1 then the probability of destroying the item is 3/4.

Row 1, Column 2 or Row 1, Column 3: If the player I drops bomb on car 1 and the item is in the car 2 or 3 then the probability of destroying the item is 0.

Row 2, Column 2 : If the player I drops bomb on car 2 and the item is in the car 2 then the probability of destroying the item is 1/4.

Row 2, Column 1 or Row 2, Column 3: If the player I drops bomb on car 2 and the item is in the car 1 or 3 then the probability of destroying the item is 0.

Row 3, Column 3 : If the player I drops bomb on car 3 and the item is in the car 3 then the probability of destroying the item is 1/2.

Row 3, Column 1 or Row 3, Column 2: If the player I drops bomb on car 3 and the item is in the car 1 or 2 then the probability of destroying the item is 0.

Finding the optimal strategy for both the players.

Let p = (p1, p2, p3) be the optimal strategy for the player I and q = (q1, q2, q3) be the optimal strategy for the player II where p1,p2,p3 are the probabilities of player I dropping the bomb on car 1,2 or 3. And q1,q1,q3 are the probabilities of player II putting items in car 1,2 or 3.

Let V be the value of the game.

Solving the equations derived from the pay off matrix , 3/4p1 = V,

1/4p2 = V,

1/2p3=V

and p1+p2+p3=1

p1 = 4/3V, p2=4V, p3=2V

4/3V + 4V + 2V = 1

or, V = 3/22

so, p1 = 4/3V = 2/11, p2 = 4V = 6/11, p3=2V = 3/11

Similarly, we solve for q = (q1, q2, q3), 3/4q1 = V,

1/4q2 = V,

1/2q3=V

and q1+q2+q3=1

we get q1 = 4/3V = 2/11, q2 = 4V = 6/11, q3=2V = 3/11

So, the optimal strategies for both the players are

p = (2/11,6/11,3/11) and q= (2/11,6/11,3/11 and

the value of the game is 3/22.

5 0
4 years ago
What is the range of the function ok the graph
alexandr1967 [171]
The answer is the last answer choice:
all the real numbers greater than or equal to 2

The range of a function is all the possible y values of a function. From the function you see on the left side, it shows that the lowest value is at (1, 2) and from there it doesn't go any lower meaning all the values will be higher than 2 for the y value.
3 0
4 years ago
Help please!! I’m stuck on this
inn [45]

Answer:

2^12/2^8 is equivalent to 512 otherwise can be written as 2^9

4 0
4 years ago
A planter box can hold 3, ft of soil. The area of the base of the box is 24 ft. A sketch of the box is shown.
liraira [26]

Answer:

8

24 divided by 3= 8  

8x3=24 ft

7 0
3 years ago
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