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alisha [4.7K]
3 years ago
12

19. If AB = 10

Mathematics
2 answers:
frutty [35]3 years ago
8 0

Answer:

19. If AB = 10

units, BC = 7

units, CD = 8

units, and AD =

18 units, what

is LM?

Quadrilateral ABCD is translated down

and left to form quadrilateral OLMN.

Step-by-step explanation:

VashaNatasha [74]3 years ago
6 0

Step-by-step explanation:

Lm is the similar rib of bc

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4(5x - 2) = 72<br> What do I do
Pepsi [2]

Answer:

x = 4

Step-by-step explanation:

4(5x - 2) = 72

Do the distributive property

20x - 8 = 72

Then add 8 to both sides to get 20x alone

20x - 8 = 72

      + 8  + 8

20x = 80

Then divide both sides by 20 to get x

\frac{20x}{20} = \frac{80}{20}

x = 4

6 0
3 years ago
The expanded notation of the number 53 961 will be​
Harman [31]

50000 + 3000 + 900 + 60 + 1

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A store has been selling 100 Blu-ray disc players a week at $600 each. A market survey indicates that for each $40 rebate offere
Sav [38]

Answer:

<em>The rebate should be $220</em>

Step-by-step explanation:

<u>Demand Curve</u>

It's the relationship between price (P) and quantity (Q) demanded a certain product or service.

(a) We need to find the function that relates both magnitudes assuming a linear equation. The equation of a line can be found with the point-point formula:

\displaystyle Q-Q_1=\frac{Q_2-Q_1}{P_2-P_1}(P-P_1)

Two sets of data are given: 100 Blu-ray disc players are sold a week at $600 each. The ordered pair for this condition is (P,Q)=(600,100).

The other point comes from the market survey: The number of units sold will increase by 80 (100+80=180) when the price goes down $40 (600-40=560). The new point is (P,Q)=(560,180)

We set up the equation of the demand

\displaystyle Q-100=\frac{180-100}{560-600}(P-560)

Rearranging

-40Q+4000=80P-44800

Or

80P+40Q=48800

Simplifying

2P+Q=1120

(b) The revenue function is Q times the price

R=Q.P

Solving the equation of the demand for P

\displaystyle P=\frac{1120-Q}{2}

Thus, the revenue is

\displaystyle R=Q\cdot \frac{1120-Q}{2}

\displaystyle R=\frac{1120Q-Q^2}{2}

(c) To find the optimum value of the revenue, we take the derivative of R and equate to 0

\displaystyle R'=\frac{1120-2Q}{2}=560-Q=0

Solving

Q=560 units a week

For which the revenue is

\displaystyle R=\frac{1120(560)-560^2}{2}

R=\$156,800

And the price is

\displaystyle P=\frac{1120-560}{2}=280

P=\$280

The rebate should be $600-$280=$220

4 0
3 years ago
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