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3 years ago

Las medianas de un triángulo siempre se intersecan en su interior?

Mathematics

1 answer:

Studentka2010 [4]3 years ago

8 0

Answer:

Hola, como estas?

R/= La mediana de un triángulo es una recta que une cada vértice con el punto medio del lado opuesto. ... Comprueba moviendo los puntos A, B y C que las medianas siempre se cortan en un punto interior al triángulo.

Hi, how are you?

R/= The median of a triangle is a line that joins each vertex with the midpoint of the opposite side. ... Check by moving points A, B and C that the medians always intersect at a point inside the triangle.

Step-by-step explanation:

Espero que te ayude

Gracias por los puntos. Que tengas una buena noche. ^^

I hope it helps you

Thank you for the points. Have a nice night. ^^

You might be interested in

What is the slope of the line that contains the points (-3,5)and (-5,6)

tigry1 [53]

<span>(-3,5) (-5,6)
slope = 5-6 / -3 --5
</span><span>slope = -1 / 2

</span>

6 0

3 years ago

So, I need to find the Mean Median Mode and Range with this frequency table, and I have no idea how to do that. Can somebody ple

olya-2409 [2.1K]

Mean: average of the numbers. Add them up, divide by how many numbers/entries there are.
-2 + -1 + 0 + 0 + 0 + 0 + 2 + 4 = 3
3 divided by 8 = 0.375
Your mean is 0.375

Median: write the data in numerical order, find the middle number.

-2, -1, 0, 0, 0, 0, 2, 4
In this data set, there are an even number of entries, so we average the middle two numbers. Thankfully, here, the middle two are the same, so your median is 0.

Mode: the number that appears the most often in the data set

Your mode is also 0, because there are more zeroes than any other number in the data set.

Range: the distance on a number line between the highest and lowest number.

The distance between -2 and 4 is 6.4 - (-2) = 6

Please LMK if you have questions

8 0

3 years ago

Assume that a cross is made between a heterozygous tall pea plant and a homozygous short pea plant. Fifty offspring are produced

Butoxors [25]

Answer:

1) $\chi^2 = \frac{(30-25)^2}{25} +\frac{(20-25)^2}{25} =1 +1 =2$

2) $df = c-1 = 2-1$

Where c represent the number of categories c=2

Step-by-step explanation:

Previous concepts

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

Tall =30 , Short =20

We need to conduct a chi square test in order to check the following hypothesis:

H0: The deviations from a 1:1 ratio (25 tall and 25 short) are due to chance.

H1: The deviations from a 1:1 ratio (25 tall and 25 short) are NOT due to chance.

Part 1

So then we know that the expected values would be 25 for each case

The statistic to check the hypothesis is given by:

$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

And if we replace we got:

$\chi^2 = \frac{(30-25)^2}{25} +\frac{(20-25)^2}{25} =1 +1 =2$

Part 2

For this case the degreed of freedom are given by:

$df = c-1 = 2-1$

Where c represent the number of categories c=2

And we can calculate the p value given by:

$p_v = P(\chi^2_{1} >2)=0.157$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(2,1,TRUE)"

7 0

3 years ago

Sue planted 4 times as many apple seeds as she planted orange seeds. 15 percent of the apple seeds grew into trees, and 10 perce

tatiyna

Answer: 600

Step-by-step explanation:

Given : Sue planted 4 times as many apple seeds as she planted orange seeds. 15 percent of the apple seeds grew into trees, and 10 percent of the orange seeds grew into trees

Let x be the number of apply seeds and y be the number of orange seeds , the we have the following equations:-

$x=4y$ (1)