6x²+x-12
the first thing we need to do is find 2 numbers that add up to equal the middle term (1) but multiply together to get a product of -72 (-12*6)
two numbers that would fit this is 9 and -8
so now we placed 9x and -8x in place of the middle term
6x²+9x-8x-12
now we look for whats common between the first two numbers and divide them out
6x²+9x = 3x(2x+3)
now we do the same with the last two numbers
-8x-12 = -4(2x+3)
notice how the numbers in brackets are the same (2x+3)
we will keep (2x+3) and then combine the numbers on the outside
once we do that you should get an answer of
(3x-4)(2x+3)
hope this helped!
I can't see the question it's blurry
Answer:
3rd one? Someone correct me if I’m wrong
Step-by-step explanation:
First you would combine like terms on each side of the equation It would look like this... 4X+8= 4X-13
Then you would add 13 to both sides, the 13 on the right side of the equation would cancel out and the 8 would become 21. It would look like this... 4X+21=4x.
Now you would subtract 4X from both sides. The 4's Would cancel out which would leave you with 21=X
The solutions are:
x = −4,x = 7
Explanation:
X^2−3x−28= 0
We can first factorise this expression by splitting the middle term and then find the solutions:
= x^2−7x+4x−28=0
= x( x−7) + 4( x − 7)=0
=(x+4)(x−7)
Now, we can equate the two factors with zero and find the solutions:
x+4=0,x =−4x−7=0,x=7
