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mrs_skeptik [129]

2 years ago

6

Help me ans should be well explained

2 answers:

seraphim [82]2 years ago

6 0

<h3>Length (L) of Rectangle = 40 m </h3><h3>Breadth (B) of Rectangle = 30m</h3><h3 /><h3>Perimeter of Rectangle:-</h3>

=<em> 2(Length + Breadth)</em>

<em>=</em><em> </em><em>2</em><em>(</em><em>40</em><em> </em><em>+</em><em> </em><em>30</em><em>)</em>

<em>=</em><em> </em><em>2</em><em>(</em><em>70</em><em>)</em>

<em>=</em><em> </em><em>1</em><em>4</em><em>0</em><em>m</em>

<h3>Area of Rectangle:-</h3>

<em>=</em><em> </em><em>L</em><em>e</em><em>n</em><em>g</em><em>t</em><em>h</em><em> </em><em>×</em><em> </em><em>B</em><em>r</em><em>e</em><em>a</em><em>d</em><em>t</em><em>h</em>

<em>=</em><em> </em><em>40</em><em> </em><em>×</em><em> </em><em>30</em>

<em>=</em><em> </em><em>1200</em><em>m</em><em>^</em><em>2</em>

<em>Therefore, </em><em>T</em><em>h</em><em>e</em><em> </em><em>p</em><em>e</em><em>r</em><em>i</em><em>m</em><em>e</em><em>t</em><em>e</em><em>r</em><em> </em><em>o</em><em>f</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>r</em><em>e</em><em>c</em><em>t</em><em>a</em><em>n</em><em>g</em><em>l</em><em>e</em><em> </em><em>i</em><em>s</em><em> </em><em>140</em><em>m</em><em> </em><em>a</em><em>n</em><em>d</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>a</em><em>r</em><em>e</em><em>a</em><em> </em><em>o</em><em>f</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>r</em><em>e</em><em>c</em><em>t</em><em>a</em><em>n</em><em>g</em><em>l</em><em>e</em><em> </em><em>i</em><em>s</em><em> </em><em>1200</em><em>m</em><em>^</em><em>2</em><em>.</em>

rusak2 [61]2 years ago

4 0

Length=L=40m
Breadth=B=30m

Perimeter:-

$\\ \sf\longmapsto 2(L+B)$

$\\ \sf\longmapsto 2(40+30)$

$\\ \sf\longmapsto 2(70)$

$\\ \sf\longmapsto 140m$

Area

$\\ \sf\longmapsto LB$

$\\ \sf\longmapsto 40(30)$

$\\ \sf\longmapsto 1200m^2$

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Use the Polynomial Identity below to help you create a list of 10 Pythagorean Triples:

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(3,4,5)

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(5,12,13)

(8,15,17)

(12,16,20)

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(20,21,29)

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(9,40,41)

Just choose 2 numbers from {1,2,3,4,5,6,7,8,...} and make sure the one you input for x is larger.

Post the three in the comments and I will check them for you.

Step-by-step explanation:

We need to choose 2 positive integers for x and y where x>y.

Positive integers are {1,2,3,4,5,6,7,.....}.

I'm going to start with (x,y)=(2,1).

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$(4+1)^2=(4-1)^2+(4)^2$

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I'm going to choose (x,y)=(3,1).

x=3 and y=1.

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So another Pythagorean Triple is (6,8,10).

I'm going to choose (x,y)=(3,2).

x=3 and y=2.

$(3^2+2^2)^2=(3^2-2^2)^2+(2\cdot3\cdot2)^2$

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So another is (5,12,13).

I'm going to choose (x,y)=(4,1).

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Another is (8,15,17).

I'm going to choose (x,y)=(4,2).

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I'm going to choose (x,y)=(4,3).

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I will do one more.

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5 0

3 years ago

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Answer:

36.25 and 307.18

Step-by-step explanation:

both are 100 times greater than 20.342.

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