First you subtract the two equations
x^2-2x+3-6x
You simplify that and get
x^2+4x+3 = 0
Now we solve using the quadratic formula.
We get x = -1 and x = -3.
Now we find the y values by plugging the x values into the equation.
f(x) is the same as y.
y = (-1)^2 - 2(-1) + 3
y = 1+2+3
y = 6
Now for the other x value.
y = (-3)^2 - 2(-3) + 3
y = 9+9
y = 18
So the two ordered pairs are (-1,6) and (-3,18)
Yea it is.4\5 is greater than 2
Answer: 4 units
Step-by-step explanation:
The given position function:
, where t≥0.
To determine: Total distance traveled by the particle from 0≤ t ≤ 4.0.
At t=0,

At, t=4,

Total distance traveled by the particle from 0≤ t ≤ 4.0 = |42-38| units
= 4 units
Hence, the distance traveled by the particle from 0≤t≤4.0 is 4 units.
Answer:
The <em>p-</em>value of the test is 0.106.
The null hypothesis will be accepted at 5% level of significance.
Step-by-step explanation:
The hypothesis test is left-tailed.
The test statistic value is: <em>z</em> = -1.25.
The significance level of the test is: <em>α</em> = 0.05.
The <em>p</em>-value of a left-tailed hypothesis test is:

The <em>p-</em>value of the test is 0.106.
**Use the <em>z-</em>table for the probability.
<u>Decision rule:</u>
If the <em>p</em>-value is less than the significance level the null hypothesis will be rejected and if it is more than the significance level the null hypothesis will be accepted.
The <em>p</em>-value = 0.106 > <em>α</em> = 0.05.
The null hypothesis will be accepted at 5% level of significance.
Answer:
Go through the explanation you should be able to solve them
Step-by-step explanation:
How do you know a difference of two square;
Let's consider the example below;
x^2 - 9 = ( x+ 3)( x-3); this is a difference of two square because 9 is a perfect square.
Let's consider another example,
2x^2 - 18
If we divide through by 2 we have:
2x^2/2 -18 /2 = x^2 - 9 ; which is a perfect square as shown above
Let's take another example;
x^6 - 64
The above expression is the same as;
(x^3)^2 -( 8)^2= (x^3 + 8) (x^3 -8); this is a difference of 2 square.
Let's take another example
a^5 - y^6 ; a^5 - (y ^3)^2
We cannot simplify a^5 as we did for y^6; hence the expression is not a perfect square
Lastly let's consider
a^4 - b^4 we can simplify it as (a^2)^2 - (b^2)^2 ; which is a perfect square because it evaluates to
(a^2 + b^2) ( a^2 - b^2)