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ruslelena [56]
3 years ago
6

Identify the property that is used in each statement. HELP ME PLEASE DUE IN 15 minutes!!!??

Mathematics
1 answer:
Dafna1 [17]3 years ago
5 0

Answer:

65

Step-by-step explanation:

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HELP HELP HELP HELP HELP HELP HELP PLEASEEEEEEEEEEEEEEES
Akimi4 [234]

Answer:

600

Step-by-step explanation:

6 x 6 x 10 = 360

6 x 4 x 10 = 240

360 + 240 = 600

Multiply base times height for area of triangle, multiply that by the depth (10m)

4 0
3 years ago
Two researchers conducted a study in which two groups of students were asked to answer 42 trivia questions from a board game. Th
denpristay [2]

Answer:

(1) Correct option is B.

(2) Correct option is C.

Step-by-step explanation:

The information provided is:

n_{1}=200,\ \bar x_{1}=22.7,\ s_{1} = 4.5\\n_{2}=200,\ \bar x_{2}=19.7,\ s_{2} = 4.3

The (1 - <em>α</em>)% confidence interval for the difference between two mean is:

CI=\bar x_{1}-\bar x_{2}\pm t_{\alpha/2, (n_{1}+n_[2}-2}\sqrt{\frac{s_{1}^{2}}{n_{1}}+\frac{s_{2}^{2}}{n_{2}} }

The critical value of <em>t</em> is:

\alpha /2=0.05/2=0.025

degrees of freedom =n_{1}+n_{2}-2=200+200-2=398

t_{\alpha/2, n_{1}+n_{2}-2}=t_{0.025, 398}=1.96

Compute the 95% confidence interval for the difference between two mean as follows:

CI=22.7-19.7\pm 1.96\sqrt{\frac{4.5^{2}}{200}+\frac{4.3^{2}}{200} }\\=3\pm0.8624\\=(2.1376, 3.8624)\\\approx(2.14, 3.86)

Thus, the 95% confidence interval, (2.14, 3.86) implies that the true mean difference value is contained in this interval with probability 0.95.

Correct option is B.

The null value of the difference between means is 0.

As the value 0 is not in the interval this implies that there is a difference between the two means, concluding that priming does have an effect on scores.

Correct option is C.

4 0
3 years ago
What is the sigh of 48 2/9 + (-39 8/9)
Elden [556K]

Answer:

NEGATIVE SIGH

Step-by-step explanation:

The Answer is 24

7 0
3 years ago
Read 2 more answers
In rectangle ABCD, find x and y.
soldier1979 [14.2K]
Answer: x=5 y=6

Step-by-step explanation: 6y=3× +21
6y-6=2× +20
Opposite sides of the rectangle are equal
Substitute 3x +21 into 6y in the second equation.



8 0
2 years ago
Solve the system of equations.
Xelga [282]

Answer:

  b.  x=1, y=2, z=3

Step-by-step explanation:

The system of equations ...

  • 3x +2y +z = 10
  • 9x -6y +z = 0
  • x -y -3z = -10

has solution (x, y, z) = (1, 2, 3) . . . . matches choice B.

_____

While it is convenient to solve this using a graphing calculator or web site, one can easily solve the system by hand.

Subtract the second equation from 3 times the first:

  3(3x +2y +z) -(9x -6y +z) = 3(10) -(0)

  12y + 2z = 30 . . . . simplify

Dividing this result by 2 gives ...

  6y +z = 15 . . . . . . [eq4]

Subtract 3 times the third equation from the first:

  (3x +2y +z) -3(x -y -3z) = (10) -3(-10)

  5y +10z = 40 . . . . simplify

  y + 2z = 8 . . . . . . . divide by 5 . . . . . [eq5]

The two equations [eq4] and [eq5] can be solved any of the ways you usually solve two equations in two variables. Here, we'll use the first equation to write an expression for z that we can substitute into the second equation.

  z = 15 -6y . . . . . subtract 6y from [eq4]

  y + 2(15 -6y) = 8 . . . . . substitute for z in [eq5]

  -11y +30 = 8 . . . . . simplify

  -11y = -22 . . . . . . . subtract 30

  y = 2 . . . . . . . . . . . divide by the coefficient of y

  z = 15 -6(2) = 3 . . . . substitute for y in our equation for z

Substituting these values for y and z into the third original equation gives ...

  x - 2 -3(3) = -10

  x -11 = -10 . . . . . . . . simplify

  x = 1 . . . . . . . . . . . . add 11

The solution to the above system of equations is (x, y, z) = (1, 2, 3).

_____

<em>Comment on the problem statement</em>

Math is generally unforgiving of imprecision. The given system of equations has no variable "z", and some other typos are apparently involved. That is why we rewrote the system to the equations shown above.

It is very easy to mistake z for 2, or g for 9, or o for 0, or 1 for 7. There are other confusions that are possible, as well. Letters I (eye) and l (ell) are easily confused, and may be confused with 1 (one) as well. Sometimes y and 4, or 4 and 9, can also be written so as to be difficult to tell apart. Great care must be taken when handwriting these symbols.

7 0
4 years ago
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