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tester [92]
2 years ago
11

Which are monomials? -7 a x + y 24r2st3 bx

Mathematics
2 answers:
amid [387]2 years ago
8 0

Answer:

Step-by-step explanation:

dedylja [7]2 years ago
3 0

Answer:

A,B,E,F

Step-by-step explanation:

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Simplify 42 ⋅ 48. Can someone please help me?
weqwewe [10]

your answer is 2016


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3 years ago
Rod smokes 1 1/2 packs of cigarettes per day. Rod buys cigarettes by the carton. There are ten packs of cigarettes in each carto
nadezda [96]

Answer:

It costs Rod $5.37 per day to smoke.

Step-by-step explanation:

If a carton costs 35.80 and there are 10 packs per carton

$35.80 /10 = 3.58 per pack

Rod smokes 1.5 packs per day

1.5 * 3.58 = $5.37

It costs Rod $5.37 per day to smoke.

3 0
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I NEED HELP AP STATS THANK YOU!!
artcher [175]

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it is true :)

Step-by-step explanation:

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3 years ago
Witch of the following are the factors of 4b^2 - 16?
luda_lava [24]
<span>4b^2 - 16 = (2b + 4)(2b - 4)

</span>difference of squares<span> 
a^</span>2<span> – b^</span>2<span> = (a + b)(a – b) </span><span>

</span>
4 0
3 years ago
A real estate agent has 8 master keys to open several new homes. Only 1 master key will open any given house. If 40% of these ho
riadik2000 [5.3K]

Answer:

Step-by-step explanation:

Suppose F represents the value that a room is unlocked.

Then, we can assume that the probability of unlocked homes is:

P(unlocked homes) = P(U)

P(unlocked homes) = 40%

P(unlocked homes) = 0.40

Also, let us represent the value of the locked room with G.

P(locked homes) = P(G)

P(locked homes) = (1 - 0.40)

P(locked homes) = 0.60

Let the probability of selecting a correct key be P(S)

It implies that for the agent to use 3 keys, we have a combination of ^8C_3 possible ways for the set of keys.

Now; since only one will open the house, then:

P(select correct key) = P(S)

P(S) = \dfrac{ (^1_1) (^7_2)   }{   ^8_3 }

P(S) = \dfrac{21}{56}

P(S) = 0.375

Finally, for the real estate agent to have access to specific homes supposing the agent select three master keys at random prior to the time he left his office, Then:

P(F ∪ (G∩S) = P(F) + P(G∩S)

P(F ∪ (G∩S) = P(F) + P(G) × P(S)

P(F ∪ (G∩S) = 0.40 + (0.60×0.375)

P(F ∪ (G∩S) = 0.40 + 0.225

P(F ∪ (G∩S) =0.625

5 0
2 years ago
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