First, write an equation system based on the problem
An equation for "the perimeter of a rectangle is 70 in" can be written as following
∴ 2l + 2w = 70 <em>(first equation)</em>
An equation for "the length is 11 in more than its width" can be written as following
∴ l = w + 11 <em>(second equation)</em>
Second, solve the equation by substitution method o find the dimension of the rectangle.
Substitute/plug l as (w+11) into the first equation
2l + 2w = 70
2(w + 11) + 2w = 70
2w + 22 + 2w = 70
4w + 22 = 70
4w = 70 - 22
4w = 48
w = 48/4
w = 12
The width of the rectangle is 12 in
Substitute w with 12 to the second equation
l = w + 11
l = 12 + 11
l = 23
The length of the rectangle is 23 in
Third, find the area of the rectangle
a = l × w
a = 23 × 12
a = 276
The area of the rectangle is 276 in²
Approximately 3.849 is the cube root of 57 cube root.
In this problem, we are given the equations of the two sides
of a rhombus.
Equation 1 is 4 x – 10
Equation 2 is 2 x + 20
Since the given shape is a rhombus, therefore the two sides
have equal sides. Hence, we can simply equate equation 1 and equation 2:
4 x – 10 = 2 x + 20
2 x = 30
x = 15
Therefore the answer is:
A. 15
It depends on the given information.
McKenzie's work is correct if the two short sides are given as 5 and 13.
Cara's work is correct is almost correct if 5 is one leg, and 13 is the hypotenuse. The exact answer is 12, but she wrote it as approximately equal. That's her only problem.
By the way, Ddssaa122: when posting questions, the power of a number is written as 5^2 and not 52. If you copy and paste, please make sure you add the caret sign to indicate a power, or else you will suffer by getting a wrong answer. 5^2=5*5, 52=4*13, so they are not the same.
Answer:
40
Step-by-step explanation:
1/4 is one fourth of 1 cup then multiple that by 10. 4x10 =40
