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2 years ago

Please help! I neeeeeeeeeeeeddddddddd HELP!

Mathematics

2 answers:

Pavlova-9 [17]2 years ago

8 0

It’s definitely 400!!

brilliants [131]2 years ago

3 0

Answer:

probably 400 its closest to what i got

Step-by-step explanation:

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Find next two terms. 10, -40, 160, ?,?

bija089 [108]

Answer: -640, 2560

each number in the sequence is multiplied by -4 to get the next answer

3 0

2 years ago

If a child's knowledge of the alphabet is limited to the letters a, b, c, i, and e, and if the child writes two letters at rando

sweet [91]

A- 6/25 you can use A 4 times the other letters you can ether use 2 time or 1 time.

6 0

3 years ago

Read 2 more answers

A total of 30 percent of the geese included in a certain migration study were male. If some of the geese migrated during the stu

Serggg [28]

<h2>Answer:</h2>

(B). $\frac{7}{12}$

<h2>Step-by-step explanation:</h2>

In the question,

Let the total number of geese be = 100x

Number of Male geese = 30% = 30x

Number of Female Geese = 70x

Let us say 'kx' geese migrated from these geese.

Number of migrated Male geese = 20% of kx = kx/5

Number of migrated Female geese = 4kx/5

So,

Migration rate of Male geese is given by,

$\frac{(\frac{kx}{5})}{30x}$

Migration rate of Female geese is given by,

$\frac{(\frac{4kx}{5})}{70x}$

So,

The ratio of Migration rate of Male geese to that of Female geese is given by,

$\frac{\left[\frac{(\frac{kx}{5})}{30x}\right]}{\left[\frac{(\frac{4kx}{5})}{70x}\right]}=\frac{350}{4\times 150}=\frac{7}{12}$

Therefore, the ratio of the rate of migration of Male geese to that of Female geese is,

$\frac{7}{12}$

Hence, the correct option is (B).

6 0

3 years ago

We're working with single variable equations and I'm okay at them, but I'm rusty when it comes to using it with fractions. If an

jasenka [17]

Answer: v=-18/5

Step-by-step explanation:

Assuming you want to solve for v, we need to use our algebraic properties.

$\frac{v}{3}+2=\frac{4}{5}$ [subtract both sides by 2]

$\frac{v}{3}=-\frac{6}{5}$ [multiply both sides by 3]

$v=-\frac{18}{5}$

Now, we know that v=-18/5.

3 0

3 years ago

Data collected at Toronto Pearson International Airport suggests that an exponential distribution with mean value 2725hours is a

Ivan

Answer:

a) What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

$P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48$

At most 3 hours?

$P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667$

b) What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

$P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X$

What is the probability that it is less than the mean value by more than one standard deviation?

$P(X$

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

$P(X=x)=\lambda e^{-\lambda x}$