Problem
For a quadratic equation function that models the height above ground of a projectile, how do you determine the maximum height, y, and time, x , when the projectile reaches the ground
Solution
We know that the x coordinate of a quadratic function is given by:
Vx= -b/2a
And the y coordinate correspond to the maximum value of y.
Then the best options are C and D but the best option is:
D) The maximum height is a y coordinate of the vertex of the quadratic function, which occurs when x = -b/2a
The projectile reaches the ground when the height is zero. The time when this occurs is the x-intercept of the zero of the function that is farthest to the right.
9514 1404 393
Answer:
- area: 114 square units
- perimeter: 44 units
Step-by-step explanation:
The figure is a trapezoid with bases 12 and 7, and a height of 12. The area formula is ...
A = (1/2)(b1 +b2)h
A = (1/2)(12 +7)(12) = 114 . . . square units area
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The length of side AB can be found using the distance formula:
d = √((x2 -x1)^2 +(y2 -y1)^2)
d = √((6 -(-6))^2 +(1 -6)^2) = √(144 +25) = 13
The sum of the side lengths is then ...
13 +7 +12 +12 = 44 . . . units perimeter
