Hello :
sin(x) + cos(x) = √2(1/√2 sin(x) +1/√2 cos(x))
but : 1/√2 = cos(π/4) = sin(<span> π/4)
</span>sin(x) + cos(x) = √2( cos(π/4)sin(x) + sin( π/4) cos(x)) =√2<span>sin(x + π/4)
</span>because : cos(π/4)sin(x) + sin( π/4) cos(x)=sin(x + π/4) by identity :
sin(a+b) = sina cosb +cosa sinb
After you re-arrange the equation, you'll find out that you got y=3x+6....okay, this equation is a linear equation, you can use y=mx+b {where m=3, and b=6}. then to find the co-ordinate of (x,y) which is the point, substitute 1,2,3,4.... for x in 'y=3x+6' to figure out the co-ordinate of y.
answer: (1,14), (2,16), (3,19), (4,22)
Answer: tye
Step-by-step explanation:
Answer:
You can see that Y is obviously bigger than X
Step-by-step explanation:
Answer:
a.) -20p - 2
Step-by-step explanation:
