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kakasveta [241]
2 years ago
15

What is the y- intercept of a line that goes through the points (3,-2)& has a slope of -4?

Mathematics
1 answer:
Liula [17]2 years ago
6 0

Answer:

Y-intercept = 10

Step-by-step explanation:

Point (3, - 2)

y-intercept = -2 - (-4)(3)

= - 2 - - 12

= - 2 + 12 = 10

y = -4x + 10

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Answer:

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Step-by-step explanation:

Given:

The two points on the line are:

(x_1,y_1)=(-6,-3)\\(x_2,y_2)=(6,-7)

Now, for a line with two points on it, the slope of the line is given as:

m=\frac{y_2-y_1}{x_2-x_1}

For the points (x_1,y_1)=(-6,-3)\ and\ (x_2,y_2)=(6,-7), slope is:

m=\frac{-7-(-3)}{6-(-6)}\\m=\frac{-7+3}{6+6}\\m=\frac{-4}{12}=-\frac{1}{3}

Now, for a line with slope 'm' and a point (x_1,y_1) on it is given as:

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Plug in all the values and determine the equation of the line. This gives,

y-(-3)=-\frac{1}{3}(x-(-6))\\\\y+3=-\frac{1}{3}(x+6)\\\\y+3=-\frac{1}{3}x-\frac{1}{3}\times 6\\\\y+3=-\frac{1}{3}x-2\\\\y=-\frac{1}{3}x-2-3\\\\y=-\frac{1}{3}x-5

Therefore, the equation of the line is:

y=-\frac{1}{3}x-5

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3 years ago
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Step-by-step explanation:

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